我试图检索所有没有保留连接到某个“huisnummer”(housenumber)的房屋。 SELECT * FROM huis WHERE NOT EXISTS(select * FROM reservering WHERE reservering.huisnummer = huis.huisnummer)
,当我在我的本地主机的phpmyadmin执行的代码我得到一个错误: Keyword
我有以下SQL: SELECT
M.*
FROM
(
SELECT MAX(counter) AS FirstUserDate, imdb_id, language, season, aufloesung, episode
FROM autofehlerserie
GROUP BY imdb_id, language
) foo