我无法弄清楚下面的代码的语法问题。当我运行它,我得到错误 ORA-00907: missing right parenthesis 任何人都可以指出我的缺点吗? CREATE OR REPLACE VIEW LATESTAPPLICATIONS AS
SELECT *
FROM application_history
WHERE entry_time IN
(SELECT entr
我每次运行此查询,我得到ora00907错误: ORA-00907: missing right parenthesis 00907. 00000 - "missing right parenthesis" SELECT COUNT(*)
FROM jobseekerprofile
JOIN userprofile on jobseekerprofile.portalprofi
不知道为什么它一直说缺少右括号,它强调(*)的错误。请帮忙,谢谢。 SELECT FIRST, LAST
FROM OFFICERS
WHERE OFFICER_ID IN (SELECT OFFICER_ID FROM CRIME_OFFICERS COUNT(*) as TotalReportsOfficer
GROUP BY OFFICER_ID
我查询我放入事先准备好的声明是: select *
from (select seq, audit_ts, message_type
from log2
where 1 = 1
and message_type in ('SOURCE', 'DEST')
order by seq desc)
where ROWNUM <= ?
我有这样的语法对于Oracle: select 'Tanggal : '||to_char(c,'DD-MON-YYYY hh:mm:ss')||',' as Tgl,
case
when (select ((a.sk/b.tot)*100)
from (select count(to_char(response))sk
from log where res
我创建这样 CREATE TABLE ARTIST (
ArtistID Int NOT NULL IDENTITY(1,1),
LastName Char(25) NOT NULL,
FirstName Char(25) NOT NULL,
Nationality Char(30) NULL,
DateOfBirth