我想这个方法传递: QScriptValue ScriptProcessContext::construct(QScriptContext * ctx, QScriptEngine *)
{
return this->newInstance();
}
到QScriptEngine::newFunction。我尝试了以下选项: 如文档and also this example co
class Base { int type; };
class Derived1 : public Base { ... };
class Derived2 : public Base { ... };
class Container
{
public:
Derived1 f1;
Derived2 f2;
};
Container c;
size_t off
考虑以下代码: struct AA
{
int& rr;
};
有没有办法获得指针(或者引用)AA::rr为了获得这个? AA* aa;
auto mm = &AA::rr; // error: cannot create pointer to reference member ‘AA::rr’
aa ->* mm;
而且在gcc-7.0.1decltype(AA::mm
我无法在从void*投下的对象上调用指向成员函数的指针。见下面的例子: class Test
{
public:
Test(int pointTo)
{
if (pointTo == 1)
function = &Test::Function1;
else
function = &Test::Function2;
模板typedef s可能与using。我怎样才能直接制作模板化方法指针? 例子: class MyClass {
template<bool B> void fnc() { /*...*/ };
// Now I can do:
template<bool B>
using TempPtr = decltype(&MyClass::fnc<B>);