这里的中间就是我有这么远 $awards_sql_1 = mysql_query('SELECT * FROM categories WHERE section_id = 1') or die(mysql_error());
$awards_sql_2 = mysql_query('SELECT * FROM categories WHERE section_id = 2') or die(my
好难倒了,所以我也跟着在这个问题上的意见:Stumped in the middle of a PHP loop 但现在,我有比以前更多的问题。这是我到目前为止有: $sql = "SELECT section_name, category_name, result_level, url, winner FROM 2009_RKR_bestof INNER JOIN categories ON 2
我有一个使用一个简单的while循环显示进度条,但似乎并不奏效,因为我预料的脚本: count = 1
maxrecords = len(international)
p = ProgressBar("Blue")
t = time
while count < maxrecords:
print 'Processing %d of %d' % (count, maxrecords
我是一名Python编程初学者。我写了下面的程序,但没有按照我的要求执行。这里是代码: b=0
x=0
while b<=10:
print 'here is the outer loop\n',b,
while x<=15:
k=p[x]
print'here is the inner loop\n',x,
x=x+1
b=b