1
我想在下面运行脚本,但总是获得名称字段的NULL值。MySQL JOIN返回NULL字段
SELECT u.name AS _user_name, s.name AS _school_name
FROM fwg_files AS f
LEFT JOIN users AS u ON u.id = f.user_id
LEFT JOIN user_profiles AS up ON up.user_id = u.id
LEFT JOIN school AS s ON s.id = up.profile_value
这个问题在我看来在JOIN ON学校表上,我试图选择s.id,它也返回NULL值。
表fwg_files
id | user_id
240 | 414
241 | 436
表用户
id | name
414 | Name 1
436 | Name 2
表user_profiles
user_id | profile_value
414 | "6"
436 | "14"
表学校
id | name
6 | School 1
14 | School 2
谢谢
请从用户显示一个记录每表的UserProfiles – cja 2013-02-26 11:06:48