显示员工姓名，部门名称，薪水，年级，经验（EX：XX年YY月ZZ天）SQL的所有员工

Question

请在以下查询帮助 显示员工姓名，部门名称，薪水，等级，经验（EX：XX年YY月ZZ日）的所有员工

ENAME  DNAME SAL GRADE  EXPERIENCE 

SCOTT RESEARCH 3000 4  12 Years 3 months 15 days 

这样，我需要得到的输出。

我试图写高达年，但月，日我不能够得到。

select distinct ename,dname,sal,grade, 
(round((months_between(sysdate,hiredate)/12))||' years' EXP 
from emp,salgrade,dept 
where dept.deptno=emp.deptno and sal between losal and highsal; 

Answer 1

这里，我已经有了一个工作的T-SQL（SQL Server）的解决方案（基于测试至今）。可悲的是我没有一个Oracle实例上播放，但希望这不应该是太难转换：

declare @fromDate date = '2010-11-21' 
, @toDate date = getutcdate() 

--from date must be before to date 
declare @tempDate date 
if @toDate < @fromDate 
begin 
    set @tempDate = @toDate 
    set @toDate = @fromDate 
    set @fromDate = @tempDate 
end 

declare @fDD int = datepart(dd,@fromdate) 
, @tDD int = datepart(dd,@todate) 
, @fMM int = datepart(mm,@fromdate) 
, @tMM int = datepart(mm,@todate) 
, @fYYYY int = datepart(yyyy,@fromdate) 
, @tYYYY int = datepart(yyyy,@todate) 
, @y int, @m int, @d int 

--calc difference in years 
set @y = @tYYYY-@fyyyy 
if @fMM > @tMM or (@fMM=@tMM and @fDD > @tDD) 
begin 
    set @y = @y - 1 
    set @fYYYY = @fYYYY + @y 
    set @tempDate = DATEADD(year,@y,@fromDate) 
end 

--calc remaining difference in months 
set @m = DATEDIFF(month,@tempDate,@toDate) 
if @tDD < @fDD 
begin 
    set @m = @m-1 
    set @tempDate = DATEADD(month,@m,@tempDate) 
end 

--calc remaining difference in days 
set @d = DATEDIFF(day,@tempDate,@toDate) 

--display results in user friendly and grammatically correct way 
select cast(@y as nvarchar(3)) + N' year' + case when @y = 1 then N'' else N's' end + N' ' 
+ cast(@m as nvarchar(2)) + N' month' + case when @m = 1 then N'' else N's' end + N' ' 
+ cast(@d as nvarchar(3)) + N' day' + case when @d = 1 then N'' else N's' end + N' ' 

Answer 2

你已经有这么多年了。

使用MONTHS_BETWEEN(date1, date2)拿到个月。然后减去（年* 12）。

使用DAYS_BETWEEN(date1, date2)得到的天数。

See this for more details

Answer 3

下面是Oracle SQL你需要的答案

select (floor(months_between(sysdate,hiredate)/12)) YEARS, 
round(((months_between(sysdate,hiredate)/12)-(round(months_between(sysdate,hiredate)/12)))*12) months 
from abc;