将键映射到Python字典中的值

Question

正在努力获取字典键和值以正确排列。

import pprint 

old_dict = {'A B':['C D'],'E F':['G H'],'I J':['K L'],'M N':['O P'],'Q R':['S T'], 'U V':['W X']} 
new_dict = {} 

for x in old_dict: 
    try: 
     for i in range(0,2): 
      key = x.split()[i] 
      value = old_dict[x][0].split()[i] 
      new_dict[key] = value 
    except: 
     pass 

pprint.pprint(new_dict) 

上面的代码工作正常，返回：

{'A': 'C', 
'B': 'D', 
'E': 'G', 
'F': 'H', 
'I': 'K', 
'J': 'L', 
'M': 'O', 
'N': 'P', 
'Q': 'S', 
'R': 'T', 
'U': 'W', 
'V': 'X'} 

唯一的问题是，当我改变old_dict是以下几点：

old_dict = {'AB':['C D'],'E F':['GH'],'IJ':['KL'],'M N':['O P'],'Q R':['S T'], 'U V':['W X']} 

它返回：

{'AB': 'C', 
'E': 'GH', 
'IJ': 'KL', 
'M': 'O', 
'N': 'P', 
'Q': 'S', 
'R': 'T', 
'U': 'W', 
'V': 'X'} 

我想跳过k不用空格分隔的eys与空格分隔的值配对，也跳过非空格分隔的值与空格分隔的键配对（即，我想跳过'AB'：'C'，'E'： 'GH'， - 上面例子中的其余部分都没问题）。

我该怎么办？

Answer 1

试试这个：

import pprint 
old_dict = {'AB':['C D'],'E F':['GH'],'I J':['K L'],'M N':['O P'],'Q R':['S T'], 'U V':['W X']} 
new_dict = {} 

for x in old_dict: 
    for i in range(0,2): 
     if ' ' in x: 
     key = x.split()[i] 
     else: 
     key = x.replace("", " ")[1:-1] 
     key = key.split()[i] 
     if ' ' in old_dict[x][0]: 
     value = old_dict[x][0].split()[i] 
     else: 
     value = old_dict[x][0].replace("", " ")[1:-1] 
     value = value.split()[i] 

     new_dict[key] = value 

pprint.pprint(new_dict) 

Answer 2

我我的手机上这样做，所以我真的不能测试它的权利，但这个应该这样做：

d = {'A B':['C D'],'E F':['G H'],'I J':['K L'],'M N':['O P'],'Q R':['S T'], 'U V':['W X']} 
answer = {} 

for k in d: 
    k = k.split() 
    if len(k) == 1: continue 
    v = d[k][0].split() 
    if len(v) == 1: continue 

    for a,b in zip(k,v): 
     answer[a] = b 

Answer 3

测试正常工作：

import pprint 

old_dict = {'AB':['C D'],'E F':['GH'],'I J':['K L'],'M N':['O P'],'Q R':['S T'], 'U V':['W X']} 
new_dict = {} 

for x in old_dict: 
    try: 
     for i in range(0,2): 
      key = x.split()[i] 
      if len(key) == 1: 
       if len(old_dict[x][0].split()[i]) == 1: 
        value = old_dict[x][0].split()[i] 
      new_dict[key] = value 
    except: 
     pass 

pprint.pprint(new_dict) 

Answer 4

import pprint 

old_dict = {'AB':['C D'],'E F':['GH'],'IJ':['KL'],'M N':['O P'],'Q R':['S T'], 'U V':['W X']} 
new_dict = {} 

for x in old_dict: 
    try: 
     if(len(x)==len(old_dict[x][0])): 
      for i in range(0,2): 
       key = x.split()[i] 
       value = old_dict[x][0].split()[i] 
       new_dict[key] = value 
    except: 
     pass 


pprint.pprint(new_dict) 

Answer 5

你可以使用字典理解：

>>> old_dict = {'AB':['C D'],'E F':['GH'],'IJ':['KL'],'M N':['O P'],'Q R':['S T'], 'U V':['W X']} 
>>> {x: y for k, v in old_dict.items() if len(k) == len(v[0]) for x, y in zip(k.split(), v[0].split())} 
{'M': 'O', 'N': 'P', 'Q': 'S', 'IJ': 'KL', 'U': 'W', 'V': 'X', 'R': 'T'}