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我想遍历“开始节点”和“结束节点”之间的关系。 的确,我的暗号要求:迭代通过Neo4j关系并返回关系属性的最小值
MATCH (ar1:Article)-[:PART_OF]->()-[:SERIES]->(s1),
(ar2:Article)-[:PART_OF]->()-[:SERIES]->(s2),
(ar1)-[:CREATOR]->(au1:Author),
(ar2)-[:CREATOR]->(au1:Author),
p1 = (au1)-[CONTRIBUTOR*]->(au2:Author)
WITH REDUCE (edge IN relationships(p1)|weight + 1/edge.fdegree) AS
strength_au1_au2_p1,ar1 AS ar1,s1 AS s1,ar2 AS ar2,s2 AS s2,au1 AS au1,au2 AS au2
WHERE s1.name='WWW' AND s2.name='Pods' AND ar2.year >2010.0 AND ar1.year >2010.0
AND strength_au1_au2_p1<5.0
RETURN ar1,s1,ar2,s2,au1,au2,ar1.year AS calc_fuzzy_ar1_year_recent,ar2.year AS
calc_fuzzy_ar2_year_recent,strength_au1_au2_p1 AS calc_fuzzy_length_p1_short**
现在我想通过贡献者*关系(在P1)进行迭代,并得到它的每一个“fdegree”并返回的最低值(fdegree)在p1中的关系。
谢谢大家