的Neo4j：通过关系的收集和设置属性迭代索引

Question

在经典之作（我等。）{...}风格，我想通过一个有序集合迭代 - 伪代码：

for n,i in nodes 
    set node.weight = i + 1 
end 

可行？

Answer 1

是的，但不是最漂亮的事情：

MATCH ... 
WITH COLLECT(something) AS nodes 
FOREACH(i IN RANGE(0, LENGTH(nodes)) | 
    FOREACH(node IN [nodes[i]] | 
     SET node.weight = i + 1 
))