我已经创建了一个程序,它为用户提供一个输入,然后让他们输入他们想要给这个输入的数量,但是当我打印总数和金额时。然而,这是全线returing的值相同:即浮点输出不正确
总计:5.00 食品:5.00 账单:5.00 行程:5.00 的fags:5.00
代替:
总计:14.00 食品:2.00 账单:3.00 行程:4.00 的fags:5.00
int main(void)
{
float food = 0.00;
float travel = 0.00;
float bills = 0.00;
float fags = 0.00;
float total = 0.00;
float t_food, t_travel, t_bills, t_fags;
char userInput[3];
while(userInput[0] != 'X')
{
printf("Select option,\nA: Food\nB: Travel\nC: Bills\nD: Fags\nX: Exit\n");
scanf("%s", userInput);
if((userInput[0] == 'A') || (userInput[0] =='a'))
{
printf("Please enter an amount: ");
scanf("%f", &food);
printf("You have entered: %.2f\n", food);
t_food += food;
}
if((userInput[0] == 'B') || (userInput[0] =='b'))
{
printf("Please enter an amount: ");
scanf("%f", &travel);
printf("You have entered: %.2f\n", travel);
t_travel += travel;
}
if((userInput[0] == 'C') || (userInput[0] =='c'))
{
printf("Please enter an amount: ");
scanf("%f", &bills);
printf("You have entered: %.2f\n", bills);
t_bills += bills;
}
if((userInput[0] == 'D') || (userInput[0] =='d'))
{
printf("Please enter an amount: ");
scanf("%f", &fags);
printf("You have entered: %.2f\n", fags);
t_fags += fags;
}
if((userInput[0] =='X') || (userInput[0] =='x'))
{
total = t_food + t_fags + t_travel + t_bills;
printf("Total: %.2f\n", &total);
printf("Food: %.2f\n", &t_food);
printf("Travel: %.2f\n", &t_travel);
printf("Bills: %.2f\n", &t_bills);
printf("Fags: %.2f\n", &t_fags);
break;
}
}
return 0;
}
任何想法?
也许这个分解有点孤立,因为它是写我要关闭它,因为它relys用户输入...所以隔离您的问题要么逻辑,输入或输出。 – 2013-03-16 11:33:55
大声笑,哦,是的,我错过了printpers中的&符号...仍然不会发布没有reducibg问题的问题 – 2013-03-16 11:36:39