在单个表中查找多个ID匹配

Question

在SQL Server（2008）中，我想查找所有员工在一张表中具有3,4,5或4,5,6的技能。他们需要其中之一。例如，只有skillid = 4，不应该产生匹配。我如何构建这种类型的查询？

一个实例表：

pkid, empid, skillid 
1  2  3 
2  2  4 
3  2  5 
4  5  6 

在上述例子中，EMPID = 2是对于该组3,4,5的匹配。 empid = 5不是。

Answer 1

您将需要使用一个GROUP BY和HAVING子句查询：

select empid 
from t1 
where skillid in (3, 4, 5) 
    or skillid in (4, 5, 6) 
group by empid 
having count(distinct skillid) = 3 

见SQL Fiddle with Demo

Answer 2

尝试

select pkid, empid 
from your_table 
where skillid in (3,4,5) or skillid in (4,5,6) 
group by pkid, empid 
having count(distinct skillid) = 3 

Answer 3

前两次的答案从无法区分受苦在（1,2,6）或（1,5,6）或（2,5,6）等中设置成员。结果必须仅显示作为ALL的成员的empid， 2,3或4,5,6。

尝试：

 
    create table Table1 (pkid int constraint PK_Table1 primary key, empid int, skillid int) 

    insert into table1 values (1,2,1) 
    insert into table1 values (2,2,2) 
    insert into table1 values (3,2,3) 
    insert into table1 values (4,3,1) 

    SELECT empid 
    FROM (
     SELECT empid, sum(t.s1) as s1, sum(t.s2) as s2, sum(t.s3) as s3, sum(t.s4) as s4, sum(t.s5) as s5, sum(t.s6) as s6 
     FROM 
     (
      select empid, 1 s1, 0 s2, 0 s3, 0 s4, 0 s5, 0 s6 
      from table1 
      where skillid = 1 
      union all 
      select empid, 0, 1, 0, 0, 0, 0 
      from table1 
      where skillid = 2 
      union all 
      select empid, 0, 0, 1, 0, 0, 0 
      from table1 
      where skillid = 3 
      union all 
      select empid, 0, 0, 0, 1, 0, 0 
      from table1 
      where skillid = 4 
      union all 
      select empid, 0, 0, 0, 0, 1, 0 
      from table1 
      where skillid = 5 
      union all 
      select empid, 0, 0, 0, 0, 0, 1 
      from table1 
      where skillid = 6 
     ) t 
     GROUP BY t.empid 
    ) tt 
    WHERE (tt.s1 = 1 and tt.s2 = 1 and tt.s3 = 1) or (tt.s4 = 1 and tt.s5=1 and tt.s6=1) 

Answer 4

EMPID IN（3,4,5）是简写EMPID = 3或EMPID = 4或EMPID = 5，所以EMPID IN 3,4,5，OR IN EMPID（ 4,5,6）与empid IN（3,4,5,6）相同。但是，我们需要避免用3,5,6或3,4,6来计算人数。你可以做这样的事情：如果你愿意，看看哪些EMPID的有两套

SELECT empid, 345 AS skillset 
FROM your_table 
WHERE skillid IN (3,4,5) 
GROUP BY empid 
HAVING COUNT(DISTINCT skillid) = 3 
UNION ALL 
SELECT empid, 456 AS skillset 
FROM your_table 
WHERE skillid IN (4,5,6) 
GROUP BY empid 
HAVING COUNT(DISTINCT skillid) = 3 

你可以把一个SELECT解决这个问题，等

Answer 5

我你原来的问题的解读是，要找到那些谁满足以下任一条件的员工：

• 他们有技能的IDS 3,4及5
• 他们有技能ID 4和5和6

（或两者）。如果这种情况下，你会想用相关子查询做这样的事情：

select * 
from employee e 
where ( exists (select * from employee_skill es3 on es3.empid = e.empid and es3.skillid = 3) 
     and exists (select * from employee_skill es3 on es3.empid = e.empid and es3.skillid = 4) 
     and exists (select * from employee_skill es3 on es3.empid = e.empid and es3.skillid = 5) 
    ) 
    OR ( exists (select * from employee_skill es3 on es3.empid = e.empid and es3.skillid = 4) 
     and exists (select * from employee_skill es3 on es3.empid = e.empid and es3.skillid = 5) 
     and exists (select * from employee_skill es3 on es3.empid = e.empid and es3.skillid = 6) 
    ) 

然而，由于你的两个目标的技能集{3，4，5}和{4，5，6}有公共子集{4,5}，我们可以简化。重构，我们得到

select * 
from employee e 
where exists (select * from employee_skill es3 on es3.empid = e.empid and es3.skillid = 4  ) 
    and exists (select * from employee_skill es3 on es3.empid = e.empid and es3.skillid = 5  ) 
    and exists (select * from employee_skill es3 on es3.empid = e.empid and es3.skillid in (3 , 6)) 

另一种方法是使用left join：

select * 
from employee e 
left join employee_skill es3 on es3.empid = e.empid and es3.skillid = 3 
left join employee_skill es4 on es4.empid = e.empid and es4.skillid = 4 
left join employee_skill es5 on es5.empid = e.empid and es5.skillid = 5 
left join employee_skill es6 on es6.empid = e.empid and es6.skillid = 6 
where es4.empid is not null 
    and es5.empid is not null 
    and ( es3.empid is not null 
     OR es6.empid is not null 
    ) 

使用left join后一种方法包含一个隐含的假设，某个员工/技能组合是在数据模型中是唯一的。如果情况并非如此，那么这种方法将需要使用select distinct以免在结果集中出现重复行。