2012-02-24 121 views
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有没有人知道一种方法来创建一个强类型数据集(嘿,不是我的想法使用它们)可序列化,以便我可以将它们作为会话状态提供程序使用AppFabric Server存储?我一直在使用InProc会话状态一段时间,并没有任何问题。只要我将会话状态移出到AppFabric Server,我就会遇到强类型数据集的一些问题。我不断收到一个错误,告诉我我的数据集不可序列化。我已经检查过,他们有Serializable属性,它们只包含可序列化的数据类型(int,string等)任何thougnts?强类型数据集的序列化

编辑:这里是堆栈跟踪:

System.Runtime.Serialization.SerializationException: The constructor to deserialize an object of type ''DataSetClasses.MyStronglyTypedDataset'' was not found. ---> System.Runtime.Serialization.SerializationException: The constructor to deserialize an object of type ''DataSetClasses.MyStronglyTypedDataset'' was not found. at System.Runtime.Serialization.ObjectManager.GetConstructor(RuntimeType t, RuntimeType[] ctorParams) at System.Runtime.Serialization.ObjectManager.CompleteISerializableObject(Object obj, SerializationInfo info, StreamingContext context) --- End of inner exception stack trace --- at System.Runtime.Serialization.ObjectManager.CompleteISerializableObject(Object obj, SerializationInfo info, StreamingContext context) at System.Runtime.Serialization.ObjectManager.FixupSpecialObject(ObjectHolder holder) at System.Runtime.Serialization.ObjectManager.DoFixups() at System.Runtime.Serialization.Formatters.Binary.ObjectReader.Deserialize(HeaderHandler handler, __BinaryParser serParser, Boolean fCheck, Boolean isCrossAppDomain, IMethodCallMessage methodCallMessage) at System.Runtime.Serialization.Formatters.Binary.BinaryFormatter.Deserialize(Stream serializationStream, HeaderHandler handler, Boolean fCheck, Boolean isCrossAppDomain, IMethodCallMessage methodCallMessage) at System.Web.Util.AltSerialization.ReadValueFromStream(BinaryReader reader) at System.Web.SessionState.SessionStateItemCollection.ReadValueFromStreamWithAssert() at System.Web.SessionState.SessionStateItemCollection.DeserializeItem(String name, Boolean check) at System.Web.SessionState.SessionStateItemCollection.get_Item(String name) at System.Web.SessionState.HttpSessionStateContainer.get_Item(String name) at System.Web.SessionState.HttpSessionState.get_Item(String name) at appt.T2SharedLibrarySetup.btnSave_Click(Object sender, EventArgs e) in D:\Application\ProblemFile.aspx.vb:line 331 at System.Web.UI.WebControls.Button.OnClick(EventArgs e) at System.Web.UI.WebControls.Button.RaisePostBackEvent(String eventArgument) at System.Web.UI.WebControls.Button.System.Web.UI.IPostBackEventHandler.RaisePostBackEvent(String eventArgument) at System.Web.UI.Page.RaisePostBackEvent(IPostBackEventHandler sourceControl, String eventArgument) at System.Web.UI.Page.RaisePostBackEvent

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你能发布你得到的异常堆栈跟踪吗? – 2012-02-25 13:09:04

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添加了上面的堆栈跟踪 – bechbd 2012-02-29 17:42:36

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这篇SO文章可能是相关的: - http://stackoverflow.com/questions/7891447/how-to-serialize-de-serialize-a-custom-dataset – 2012-02-29 17:51:59

回答

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尝试串行化/反序列化首先将对象的字节数组,你试图把它放到会话(并从那里到的AppFabric)前。这是一个例子。

 private static BinaryFormatter formatter = null; 

    private static Byte[] Serialize(object entity) 
    { 
     Logger.LogDebug(Category.Cache, "Serializing"); 
     Byte[] bytes; 
     if (formatter == null) formatter = new BinaryFormatter(); 
     using (MemoryStream stream = new MemoryStream()) 
     { 
      formatter.Serialize(stream, entity); 
      bytes = stream.ToArray(); 
     } 
     return bytes; 
    } 

    private static object DeSerialize(Byte[] bytes) 
    { 
     #region Sanitation 
     if (bytes == null) { throw new System.ArgumentNullException("bytes"); } 
     #endregion 
     Logger.LogDebug(Category.Cache, "DeSerializing"); 
     object obj; 
     if (formatter == null) formatter = new BinaryFormatter(); 
     using (MemoryStream stream = new MemoryStream(bytes)) 
     { 
      obj = formatter.Deserialize(stream); 
     } 
     return obj; 
    } 

从反序列化器中取回对象后,尝试将其转换回您的类型化数据集类型。

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这是一个强类型在Visual Studio中创建数据集,方法是添加数据集,然后将表格/ sproc拖放到设计图面上。这似乎反直观,我应该需要手动序列化/反序列化这种内置的Visual Studio功能。 – bechbd 2012-02-29 18:07:33

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我建议这样做的原因是,如果你自己对二进制文件进行序列化,你可以删除对appfabric客户端的依赖性,检查你的对象并试图找出如何序列化它本身。例如,如果客户端在类的任何成员上都找到WCF数据注释属性,则它将尝试使用您可能不想执行的NetDataContractSerializer。 – 2012-02-29 18:10:14

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您可以使用DataSet.ReadXML()或WriteXML()函数来实现所需的功能。