的Python，numpy的，矩阵

Question

A=[['2' '7' 'fas'] 
['4' '8' 'sda'] 
['1' '5' 'daf'] 
['2' '24' 'gag']] 

我怎样才能得到公正矩阵A，而不是最后的 “属性附加伤害” 每一行：

A=[['2' '7'] 
['4' '8'] 
['1' '5' ] 
['2' '24']] 

我知道，行最后一个元素[：-1]

我试着用numpy的：

A[:, ?? ] 

矩阵A是随机元素，所以我是这样想事端：A[:,end-1]，但numpy的不知道什么是结束

Answer 1

>>> arr=np.array([[1,2,3],[4,5,6],[7,8,9]]) 
>>> arr[:,:-1] 
array([[1, 2], 
     [4, 5], 
     [7, 8]]) 

Answer 2

>>> A = [ ['2', '7', 'fas'] 
     , ['4', '8', 'sda'] 
     , ['1', '5', 'daf'] 
     , ['2', '24', 'gag'] 
     ] 

>>> [ x[:-1] for x in A ] 
[['2', '7'], ['4', '8'], ['1', '5'], ['2', '24']]