pandas.io.sql返回那个表不存在，即使它存在

Question

这是我的代码，我在Windows XP上运行它，在ipython笔记本里面。

import os 
os.getcwd() # This is current working directory 

db_path = '..\\06_django\\hzmo_web\\hzmo_web\\hzmo_backup_05_2013.db' 


import sqlite3 
from pandas.io import sql 
# Create your connection. 
cnx = sqlite3.connect('db_path') 

cnx 

cur = cnx.cursor()  
cur.execute('SELECT SQLITE_VERSION()') 
data = cur.fetchone() 
print "SQLite version: %s" % data 

import contextlib 
with contextlib.closing(sqlite3.connect(db_path)) as conn: 
    conn.row_factory = sqlite3.Row 
    cursor = conn.cursor()  
    cursor.execute("SELECT name FROM sqlite_master WHERE type='table'") 
    for tablerow in cursor.fetchall(): 
     print tablerow[0] 
     #table = tablerow[0] 
     #cursor.execute("SELECT * FROM {t}".format(t = table)) 
     #for row in cursor: 
     # for field in row.keys(): 
     #  print(table, field, row[field]) 

sql.read_frame('SELECT * FROM hzmo_report;', cnx) 

我只是想选择hzmo_report表中的熊猫数据帧的所有数据，正如我在文档看到在http://pandas.pydata.org/pandas-docs/stable/io.html#sql-queries

错误我得到的是：OperationalError：没有这样的表：hzmo_report 但是，表干存在。

Here is output of my code: 
--------------------------------------------------------------------------- 
OperationalError       Traceback (most recent call last) 
<ipython-input-8-916237d66737> in <module>() 
    29   #  print(table, field, row[field]) 
    30 
---> 31 sql.read_frame('SELECT * FROM hzmo_report;', cnx) 
    32 

C:\Documents and Settings\hr1ub098\Application Data\Python\Python27\site-packages\pandas\io\sql.pyc in read_frame(sql, con, index_col, coerce_float) 
    141   column name to use for the returned DataFrame object. 
    142  """ 
--> 143  cur = execute(sql, con) 
    144  rows = _safe_fetch(cur) 
    145  columns = [col_desc[0] for col_desc in cur.description] 

C:\Documents and Settings\hr1ub098\Application Data\Python\Python27\site-packages\pandas\io\sql.pyc in execute(sql, con, retry, cur, params) 
    33 
    34   if params is None: 
---> 35    cur.execute(sql) 
    36   else: 
    37    cur.execute(sql, params) 

OperationalError: no such table: hzmo_report 

SQLite version: 3.6.21 
auth_permission 
auth_group_permissions 
auth_group 
auth_user_user_permissions 
auth_user_groups 
auth_user 
django_content_type 
django_session 
django_site 
django_admin_log 
hzmo_report 
Error on sql SELECT * FROM hzmo_report; 

有没有人有任何想法可能是什么问题？

Answer 1

cnx = sqlite3.connect('db_path') 

不应该那个参数是你创建的变量，而不是一个字符串？在上述情况下，您可能会连接到一个名为“db_path”的新数据库。

cnx = sqlite3.connect(db_path)