目前我使用下面的执行本机进程:Java本机进程超时
java.lang.Process process = Runtime.getRuntime().exec(command);
int returnCode = process.waitFor();
假设,而不是等待程序返回我想终止,如果在一定的时间量已过去。我该怎么做呢?
目前我使用下面的执行本机进程:Java本机进程超时
java.lang.Process process = Runtime.getRuntime().exec(command);
int returnCode = process.waitFor();
假设,而不是等待程序返回我想终止,如果在一定的时间量已过去。我该怎么做呢?
这是丛CommandlineUtils是怎么做的:
Process p;
p = cl.execute();
...
if (timeoutInSeconds <= 0)
{
returnValue = p.waitFor();
}
else
{
long now = System.currentTimeMillis();
long timeoutInMillis = 1000L * timeoutInSeconds;
long finish = now + timeoutInMillis;
while (isAlive(p) && (System.currentTimeMillis() < finish))
{
Thread.sleep(10);
}
if (isAlive(p))
{
throw new InterruptedException("Process timeout out after " + timeoutInSeconds + " seconds");
}
returnValue = p.exitValue();
}
public static boolean isAlive(Process p) {
try
{
p.exitValue();
return false;
} catch (IllegalThreadStateException e) {
return true;
}
}
你需要一个2线程中断调用.waitFor()线程;将需要 一些不平凡的同步,使之强劲,但基本是:
TimeoutThread:
Thread.sleep(timeout);
processThread.interrupt();
ProcessThread:
try {
proc.waitFor();
} catch (InterruptedException e) {
proc.destroy();
}
所有其他的反应是正确的,但它可以制成使用FutureTask更健壮,更高效。
例如,
private static final ExecutorService THREAD_POOL
= Executors.newCachedThreadPool();
private static <T> T timedCall(Callable<T> c, long timeout, TimeUnit timeUnit)
throws InterruptedException, ExecutionException, TimeoutException
{
FutureTask<T> task = new FutureTask<T>(c);
THREAD_POOL.execute(task);
return task.get(timeout, timeUnit);
}
try {
int returnCode = timedCall(new Callable<Integer>() {
public Integer call() throws Exception {
java.lang.Process process = Runtime.getRuntime().exec(command);
return process.waitFor();
}
}, timeout, TimeUnit.SECONDS);
} catch (TimeoutException e) {
// Handle timeout here
}
如果这样反反复复,线程池是更有效,因为它缓存的线程。
这里的句柄超时对于一个例子来说可能更健壮一些。我有一些我使用的机制,但是对于最简单的情况,使用如下形式:'catch(TimeoutException e){System.exit(-1);}' – 2012-11-10 15:49:19
类型参数不能是原始类型。请用'Integer'替换int。 – naXa 2014-09-22 15:15:23
怎么样的Groovy方式
public void yourMethod() {
...
Process process = new ProcessBuilder(...).start();
//wait 5 secs or kill the process
waitForOrKill(process, TimeUnit.SECONDS.toMillis(5));
...
}
public static void waitForOrKill(Process self, long numberOfMillis) {
ProcessRunner runnable = new ProcessRunner(self);
Thread thread = new Thread(runnable);
thread.start();
runnable.waitForOrKill(numberOfMillis);
}
protected static class ProcessRunner implements Runnable {
Process process;
private boolean finished;
public ProcessRunner(Process process) {
this.process = process;
}
public void run() {
try {
process.waitFor();
} catch (InterruptedException e) {
// Ignore
}
synchronized (this) {
notifyAll();
finished = true;
}
}
public synchronized void waitForOrKill(long millis) {
if (!finished) {
try {
wait(millis);
} catch (InterruptedException e) {
// Ignore
}
if (!finished) {
process.destroy();
}
}
}
}
根据我的要求只是修改了一下。超时在这里是10秒。如果没有退出,过程将在10秒后被破坏。
public static void main(String arg[])
{
try{
Process p =Runtime.getRuntime().exec("\"C:/Program Files/VanDyke Software/SecureCRT/SecureCRT.exe\"");
long now = System.currentTimeMillis();
long timeoutInMillis = 1000L * 10;
long finish = now + timeoutInMillis;
while (isAlive(p))
{
Thread.sleep(10);
if (System.currentTimeMillis() > finish) {
p.destroy();
}
}
}
catch (Exception err) {
err.printStackTrace();
}
}
public static boolean isAlive(Process p) {
try
{
p.exitValue();
return false;
} catch (IllegalThreadStateException e) {
return true;
}
}
如果您使用的是Java 8,你可以简单地使用新waitFor with timeout:
Process p = ...
if(!p.waitFor(1, TimeUnit.MINUTE)) {
//timeout - kill the process.
p.destroy(); // consider using destroyForcibly instead
}
请找到一个很好的做法,一些explantion这里: –
Wulfaz
2013-07-16 13:25:31