我已经下一个代码,基于一个示例使用Java UDPSocket()(没有内置的类):使用Java类异常
package BomberButti;
import java.io.*;
import java.net.*;
/**
* BomberServer
* Hier wordt de Server opgezet waarop Clients kunnen connecteren om vervolgens tegen elkaar te spelen
* @author Kaj
*/
public class BomberServer {
public BomberServer() {
waitForPlayers();
}
public static void waitForPlayers() throws Exception {
try {
DatagramSocket serverSocket = new DatagramSocket(9876); //Socket openen
byte[] receiveData = new byte[1024]; //Ontvangen gegevens
byte[] sendData = new byte[1024]; //Te verzenden gegevens
while(true) {
receiveData = new byte[1024];
//Ontvangen data (als die er is) ophalen
DatagramPacket receivePacket = new DatagramPacket(receiveData, receiveData.length);
System.out.println ("Waiting for datagram packet");
serverSocket.receive(receivePacket);
String sentence = new String(receivePacket.getData());
InetAddress IPAddress = receivePacket.getAddress();
int port = receivePacket.getPort();
System.out.println ("From: " + IPAddress + ":" + port);
System.out.println ("Message: " + sentence);
String capitalizedSentence = sentence.toUpperCase();
sendData = capitalizedSentence.getBytes();
sendData = new String("Request accepted").getBytes();
DatagramPacket sendPacket =
new DatagramPacket(sendData, sendData.length, IPAddress,
port);
serverSocket.send(sendPacket);
}
}
catch(SocketException ex) {
System.out.println("UDP Port 9876 is occupied.");
System.exit(1);
}
}
public static void main(String args[]) {
BomberServer server = new BomberServer();
}
}
当尝试运行这段代码我得到错误'未报告的异常异常;必须被呃宣告为被抛出'。
我知道这与我在waitForPlayers()方法声明后面放置的'throws Exception'有关。但是,当我删除这将抛出异常部分,我得到一个错误:serverSocket.receive(receivePacket); 'unreporter异常IOException;必须被宣布为被抛出“,所以我猜想,我尝试的两种方式都不是正确的方式。
那么我该如何做到这一点是正确的?
真诚,
卢克索
,你能否告诉我们堆栈跟踪? – Smit
也捕获IOException – Suranga