在一个日期时间列上应用日期范围的行选择

Question

在下表中，如何获取用户在'2016-12-12 00：00：00.0'和'2017-02-20之间的状态 23：59：59.999' 。结果应该是emailVerified和活跃

userid status   actionDateTime 
113  emailPending 2016-11-24 11:59:26.427 
113  emailVerified 2016-12-10 17:21:15.240 
113  Active   2017-02-07 13:24:01.330 

Answer 1

您正在寻找最大的小日期和最小更大日期。

试试这样说：

DECLARE @tbl TABLE(userid INT,[status] NVARCHAR(100),actionDateTime DATETIME); 
INSERT INTO @tbl VALUES 
(113,'emailPending',{ts'2016-11-24 11:59:26.427'}) 
,(113,'emailVerified',{ts'2016-12-10 17:21:15.240'}) 
,(113,'Active',{ts'2017-02-07 13:24:01.330'}); 

DECLARE @From DATETIME={ts'2016-12-12 00:00:00'}; 
DECLARE @To DATETIME={ts'2017-02-20 23:59:59'}; 

SELECT * FROM @tbl AS t 
WHERE t.actionDateTime >= ISNULL((SELECT MAX(x.actionDateTime) FROM @tbl AS x WHERE x.actionDateTime<@From),{d'2000-01-01'}) 
    AND t.actionDateTime <= ISNULL((SELECT MIN(x.actionDateTime) FROM @tbl AS x WHERE x.actionDateTime>@To),{d'9999-01-01'}); 

结果

userid status   actionDateTime 
113  emailVerified 2016-12-10 17:21:15.240 
113  Active   2017-02-07 13:24:01.330 

Answer 2

您可以使用BETWEEN：

SELECT DISTINCT status FROM table WHERE actionDateTime BETWEEN '2016-12-12 00:00:00.0' AND '2017-02-20 23:59:59.999' 

或通过用户：

SELECT DISTINCT userid, status FROM (
SELECT userid, status 
FROM table 
WHERE actionDateTime BETWEEN '2016-12-12 00:00:00.0' AND '2017-02-20 23:59:59.999' 
) 

基于您的评论，这可能是你需要：

WITH CTE AS (
SELECT 
    userid 
    ,status 
    ,actionDateTime as DateFrom 
    ,ISNULL(LEAD(actionDateTime, 1) OVER (PARTITION BY userid ORDER BY actionDateTime), '9999-12-31') as DateTo 
FROM table 
) 
SELECT DISTINCT userid, status 
FROM CTE 
WHERE DateTo BETWEEN '2016-12-12 00:00:00.0' AND '2017-02-20 23:59:59.999' 

Answer 3

SELECT DISTINCT status 
FROM table 
WHERE actionDateTime BETWEEN '2016-12-12 00:00:00.0' AND '2017-02-20 23:59:59.999'