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我想将我在数据库中的字段解密为字符串,并且我想在春天将其传递到控制器中。我有一个休眠类是这样的:如何在休眠时解密密码
@Id
@Column(name = "USER_ID")
private BigDecimal userId;
@Column(name = "user_name")
private String username;
@Column(name = "EMPLOYEE_ID")
private BigDecimal employeeId;
@Column(name = "encrypted_user_password")
@ColumnTransformer(write="EncryptByPassPhrase('BN1HC1T',?)", read="decrypt ('BN1HC1T',pswd)")
private String encrypted_user_password;
public BigDecimal getUserId() {
return userId;
}
public void setUserId(BigDecimal userId) {
this.userId = userId;
}
public String getUsername() {
return username;
}
public void setUsername(String username) {
this.username = username;
}
public BigDecimal getEmployeeId() {
return employeeId;
}
public void setEmployeeId(BigDecimal employeeId) {
this.employeeId = employeeId;
}
public String getEncrypted_user_password() {
return encrypted_user_password;
}
public void setEncrypted_user_password(String encrypted_user_password) {
this.encrypted_user_password = encrypted_user_password;
}
和查询的结果是:
select
karyawan0_.USER_ID as USER_ID1_0_,
karyawan0_.EMPLOYEE_ID as EMPLOYEE_ID2_0_,
decrypt('BN1HC1T',
karyawan0_.encrypted_user_password) as encrypted_user_pas3_0_,
karyawan0_.user_name as user_name4_0_
from
FND_USER karyawan0_
where
karyawan0_.user_name=?
,我得到这样的错误:
java.sql.SQLSyntaxErrorException: ORA-00904: "DECRYPT": invalid identifier
我的问题是正确的,但我得到一个错误。如何解决它?
这样的逻辑不应该在数据库层上处理我认为...创建一个服务/道,可以照顾解密密码编程。 –