2010-09-02 59 views
7

鉴于以下代码:Scala的演员异常 “上通道反应属于其他演员”

class A extends Actor { 
    def act() { 
    loop { 
     reactWithin(1000) { 
     case _ => println("A Message") 
     } 
    } 
    } 
} 

class B extends A { 
    val test = Actor.actor { 
    loop { 
     reactWithin(1000) { 
     case "B" => println("B Message") 
     } 
    } 
    } 
} 

创建乙val t = new B()的实例引发以下例外:

[email protected]: caught java.lang.AssertionError: assertion failed: react on channel belonging to other actor 
java.lang.AssertionError: assertion failed: react on channel belonging to other actor 
at scala.actors.ReplyReactor$class.reactWithin(ReplyReactor.scala:123) 
at A.scala$actors$Actor$$super$reactWithin(Tester.scala:11) 
at scala.actors.Actor$class.reactWithin(Actor.scala:613) 
at A.reactWithin(Tester.scala:11) 
at B$$anonfun$1$$anonfun$apply$mcV$sp$1.apply(Tester.scala:24) 
at B$$anonfun$1$$anonfun$apply$mcV$sp$1.apply(Tester.scala:24) 
at scala.actors.Reactor$class.seq(Reactor.scala:280) 
at A.seq(Tester.scala:11) 
at scala.actors.Reactor$$anon$3.andThen(Reactor.scala:258) 
at scala.actors.Combinators$class.loop(Combinators.scala:26) 
at A.loop(Tester.scala:11) 
at B$$anonfun$1.apply$mcV$sp(Tester.scala:23) 
at scala.actors.Actor$$anon$1.act(Actor.scala:135) 
at scala.actors.Reactor$$anonfun$dostart$1.apply(Reactor.scala:222) 
at scala.actors.Reactor$$anonfun$dostart$1.apply(Reactor.scala:222) 
at scala.actors.ReactorTask.run(ReactorTask.scala:36) 
at scala.concurrent.forkjoin.ForkJoinPool$AdaptedRunnable.exec(ForkJoinPool.java:611) 
at scala.concurrent.forkjoin.ForkJoinTask.quietlyExec(ForkJoinTask.java:422) 
at scala.concurrent.forkjoin.ForkJoinWorkerThread.mainLoop(ForkJoinWorkerThread.java:340) 
at scala.concurrent.forkjoin.ForkJoinWorkerThread.run(ForkJoinWorkerThread.java:325) 

有人请赐教,我为什么这样? :)

+0

对,我想我疯了。这个失败,同样的错误: C类延伸演员{ DEF行为(){ VAL测试= Actor.actor { reactWithin(1000){ 出口 } } reactWithin(1000){ 出口 } } } val c = new C() c.start 我在这里丢失了什么? – LeChe 2010-09-04 19:51:07

回答

6

在Actor.actor块内部,您必须使用'self'变量引用诸如react和reactWithin之类的内容,如下所示:self.reactWithin(1000)。这是为了将它们与已经从父类继承的方法区分开来。

+0

当然,我很愚蠢。谢谢你。奇怪,虽然花了两周的时间才有人回答这个问题...... :) – LeChe 2010-09-28 08:11:00

+0

+1这真的很奇怪。我想我会花很多时间调试这个,如果我没有找到这个问题+答案。谢谢 :) – fresskoma 2011-06-14 22:02:12