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我有以下几点:的js只返回表的第一行
function builTable(){
for(i = 0; i< source.Products.length; i++){
var sourceProducts = source.Products[i];
row = '<tr><td>sth</td><td>';
row += sourceProducts.Product;
row += '</td><td>';
row += sourceProducts.Bookings + '</td><td>';
row += sourceProducts.Percentage + '%' + '</td><td>';
row += sourceProducts.Transactions + '</td></tr>';
$('table').append(row);
}
}
$(document).ready(function(){
builTable();
});
它:
function builTable(){
for(i = 0; i< source.Products.length; i++){
var sourceProducts = source.Products[i];
row = '<tr><td>sth</td><td>';
row += sourceProducts.Product;
row += '</td><td>';
row += sourceProducts.Bookings + '</td><td>';
row += sourceProducts.Percentage + '%' + '</td><td>';
row += sourceProducts.Transactions + '</td></tr>';
return row;
}
}
function generateTable(){
$('table').append(builTable());
}
$(document).ready(function(){
generateTable();
});
,如果我将其更改为以下这仅附加表的第一行然而,工作正常,我想有一个更具结构化的代码,其功能服务于他们的目的:
- 一个函数用于构建表和一个用于appendi (如第一个例子所示)。
JSON格式:
var source = {
"Products": [
{
"Product": "xxxxx.com",
"Bookings": 560,
"Percentage": 55.82,
"Transactions": "xxxx.xx"
},
{
"Product": "xxxxx Mobile",
"Bookings": 487,
"Percentage": 9.12,
"Transactions": "xxxx.xx"
},
{
"Product": "xx 24-7",
"Bookings": 478,
"Percentage": 8.95,
"Transactions": "xxxx.xx"
},
{
"Product": "xxxxxx",
"Bookings": 422,
"Percentage": 7.9,
"Transactions": "xxxx.xx"
},
{
"Product": "API",
"Bookings": 315,
"Percentage": 5.9,
"Transactions": "xxxx.xx"
},
{
"Product": "API",
"Bookings": 315,
"Percentage": 2.83,
"Transactions": "xxxx.xx"
}
],
"Total": {
"Bookings": 315,
"Transactions": "xxxx.xx"
}
}
任何帮助吗?
打败我吧;) – Cameron