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我想创建一个模块,学生必须提供他/她的学生ID,密码和电子邮件以验证其帐户。如果用户输入正确的ID,密码和电子邮件,则必须出现将设置其密码的模式。有没有什么办法可以将触发器在CodeIgniter的控制器函数中切换Bootstrap模态?
查看
<form method="post" action="<?php echo site_url('mycontroller/validateStud');?>" name="formvalidate">
<div class="form-group">
<input type="text" class="form-control" name="idnum" placeholder="ID Number"/>
<br>
<input type="email" class="form-control" name="mail" placeholder="Student Email"/>
<br>
<input type="password" class="form-control" name="pin" placeholder="Student PIN"/>
<br>
<button type="submit" class="btn btn-primary" style="width: 100%;" onclick="" name="submit2" value="<?php echo $this->uri->uri_string(); ?>" id="validated">Validate</button>
</div>
</form>
<div id="myModal" class="modal fade" role="dialog">
<div class="modal-dialog">
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal">×</button>
<h4 class="modal-title">Modal Header</h4>
</div>
<div class="modal-body">
<p>Some text in the modal.</p>
</div>
<div class="modal-footer">
<button type="button" class="btn btn-default" data-dismiss="modal">Close</button>
</div>
</div>
控制器 mycontroller.php
public function validateStud()
{
$submit=$this->input->post('submit2');
$studentId=$this->input->post('idnum');
$saispin=$this->input->post('pin');
$mail=$this->input->post('mail');
$res=$this->mymodel->checkValidation($studentId, $pin, $mail);
if (isset($_POST['submit2']) && $res) { //if the three inputs matched with a student record
//Open MyModal that will set account password
}
else if(isset($_POST['submit2']) && !$res)
{
//No record found
}
else
{
redirect('index', true);
}
}
我尝试过的JavaScript,但我失败了。请赐教。任何帮助将不胜感激。 :)