我正在使用Django和Django的restframework。如何从序列化程序获取数据参数？

我不知道如何访问串行的说法。

我可以从serializer.data访问完整的JSON数据。但是当我试图获得像id这样的参数时，它会返回错误。 serializer.data.id。

我怎样才能得到它呢？我用了很多时间来进行搜索，但失败了。

我这样做是因为更新模型基于用户输入。

例如

用户输入id。
得到与id数据。
将该数据保存到数据库。

我读这篇文章非常非常感谢。

views.py

class CareerViewSet(viewsets.ModelViewSet): 
    queryset = Career.objects.all() 
    serializer_class = CareerSerializer 
    permission_classes = (IsCreateable,) 

    def perform_create(self, serializer): 
     serializer.save(nickname='test') 
     print(serializer.data) 
     print(serializer.data.id)

错误

{'id': 14, 'created': '2017-04-26T12:39:58.249038Z', 'modified': '2017-04-26T12:39:58.249538Z', 'battle_tag': 'Fortune-1130', 'nickname': 'test', 'quick_eliminations': None, 'quick_damage_done': None, 'quick_deaths': None, 'quick_final_blows': None, 'quick_healing_done': None, 'quick_objective_kills': None, 'quick_objective_time': None, 'quick_solo_kills': None, 'competitive_eliminations': None, 'competitive_damage_done': None, 'competitive_deaths': None, 'competitive_final_blows': None, 'competitive_healing_done': None, 'competitive_objective_kills': None, 'competitive_objective_time': None, 'competitive_solo_kills': None, 'games_won': None, 'competitive_rank': None, 'level': None} 
Internal Server Error: /career/ 
Traceback (most recent call last): 
    File "E:\Development\Venv\20170420\myvenv\lib\site-packages\django\core\handlers\exception.py", line 42, in inner 
    response = get_response(request) 
    File "E:\Development\Venv\20170420\myvenv\lib\site-packages\django\core\handlers\base.py", line 187, in _get_response 
    response = self.process_exception_by_middleware(e, request) 
    File "E:\Development\Venv\20170420\myvenv\lib\site-packages\django\core\handlers\base.py", line 185, in _get_response 
    response = wrapped_callback(request, *callback_args, **callback_kwargs) 
    File "E:\Development\Venv\20170420\myvenv\lib\site-packages\django\views\decorators\csrf.py", line 58, in wrapped_view 
    return view_func(*args, **kwargs) 
    File "E:\Development\Venv\20170420\myvenv\lib\site-packages\rest_framework\viewsets.py", line 83, in view 
    return self.dispatch(request, *args, **kwargs) 
    File "E:\Development\Venv\20170420\myvenv\lib\site-packages\rest_framework\views.py", line 483, in dispatch 
    response = self.handle_exception(exc) 
    File "E:\Development\Venv\20170420\myvenv\lib\site-packages\rest_framework\views.py", line 443, in handle_exception 
    self.raise_uncaught_exception(exc) 
    File "E:\Development\Venv\20170420\myvenv\lib\site-packages\rest_framework\views.py", line 480, in dispatch 
    response = handler(request, *args, **kwargs) 
    File "E:\Development\Venv\20170420\myvenv\lib\site-packages\rest_framework\mixins.py", line 21, in create 
    self.perform_create(serializer) 
    File "E:\Development\Venv\20170420\overmatch_django\overwatch\views.py", line 38, in perform_create 
    print(serializer.data.id) 
AttributeError: 'ReturnDict' object has no attribute 'id'

来源

2017-04-26 HoJunLee

serializer.data是一本字典的子类（即ReturnDict），访问它，你会香草词典：

id = serializer.data['id']

来源

2017-04-26 13:06:43

非常感谢!!!! – HoJunLee

我会推荐'id = serializer.data.get（'id'，None）'以防万一。 –

使用串行.data.get（ 'ID'）。 serializer.data.id doest不工作，因为它不是一个类对象，而是一个JSON/Dict。

来源

2017-04-26 14:05:08 Aayushi

如何从序列化程序获取数据参数？

views.py

错误

回答

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