如何将一个字符串分成几对

Question

对于我正在做的项目，我需要将输入对与输入对齐，但我无法弄清楚，我可以使用一些帮助。
如何，它是：

2209222717080109 

我多么希望它变成：

["22","09","22","27","17","08","01","09"] 

Answer 1

input = "2209222717080109" 
input.chars.each_slice(2).map(&:join) 
["22", "09", "22", "27", "17", "08", "01", "09"] 

Answer 2

Convert it to a string，convert that into an array of characters，然后取两个字符each consecutive slice和joineach of those slices在一起：

2209222717080109.to_s.chars.each_slice(2).map(&:join) 
#=> ["22", "09", "22", "27", "17", "08", "01", "09"] 

Answer 3

这很容易，一种方式是通过循环和子串。 然后你可以找到更优雅的方式。

Answer 4

"2209222717080109".scan /../ 
    #=> ["22", "09", "22", "27", "17", "08", "01", "09"]