2012-11-20 717 views

回答

11
scanf("%.2f",&x); 

,我认为这将解决问题

1

使用

scanf("%.2f",&number); 


printf("%.2f", number);

6

的完整列表

Integer display 
%d  print as decimal integer 
%6d  print as decimal integer, at least 6 characters wide 
%f  print as floating point 
%6f  print as floating point, at least 6 characters wide 
%.2f print as floating point, 2 characters after decimal point 

随着(在最后一项scanf("%.2f",&x);)所需的修改将解决您的问题

+0

你肯定是最后一个(%6.2f)的作品? – orustammanapov

+0

@orustammanapov我目前已将其删除。 – Shash

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