cout不打印函数的返回值？

Question

我正在做一个问题，我必须通过一个函数传递数组，并返回用户输入的索引范围内的最小整数。问题是cout不显示函数的返回值被称为：

谁能告诉我什么是错了吗？

#include <iostream>; 
#include <array>; 
using namespace std; 

int minInARange (int array[], int lowIndex, int highIndex); 

int main() 
{ 
    int myArray[15]; 

    for (int i = 0; i <15; i++) 
    { 
     myArray[i] = 15 + rand() % (55 - 15 + 1); 
    } 

    for (int i = 0; i < 15; i++) 
    { 
     cout << myArray[i] << " "; 
    } 
    cout << endl; 

    int lowIndex = 0; 
    int highIndex = 0; 

    cout << "Enter in a low index of the array (0-14): " << endl; 
    cin >> lowIndex; 
    cout << "Enter in a higher index of the array (0-14): " << endl; 
    cin >> highIndex; 

    cout << "The lowest number in the range of array indices is: "; 
    cout << minInARange(myArray, lowIndex, highIndex) << endl; 

    return 0; 
} 

int minInARange (int array[], int lowIndex, int highIndex) 
{ 
    int lowestNum = array[lowIndex]; 
    for (int i = 0; i < highIndex - lowIndex; i++) 
    { 
     if (array[i] < lowestNum) 
     { 
      lowestNum = array[i]; 
     } 
    } 
    return lowestNum; 
} 

Answer 1

int minInARange (int array[], int lowIndex, int highIndex) { 
    cout << "lo:" << lowIndex << " hi:" << highIndex << endl; 
    for (int i=lowIndex; i<highIndex; i++) //maybe <=, depends what you want 
    cout << "Tock:" << i << endl; 
    .... 
}