如何从Python 3中的函数打印这些返回值？

Question

我有一个家庭作业，用于模拟仿木棉花。我试图找出如何扩大该计划以解决关闭问题，并返回每个玩家的号码。我在simNGames（）中添加了一个循环来计算关闭。我想返回这些值并在摘要中打印出来。

def simNGames(n, probA, probB): 
    winsA = 0 
    winsB = 0 
    shutoutA = 0 
    shutoutB = 0 
    for i in range(n): 
     scoreA, scoreB = simOneGame(probA, probB) 
     if scoreA > scoreB: 
      winsA = winsA + 1 
     else: 
      winsB = winsB + 1 
    for i in range(n): 
     scoreA, scoreB = simOneGame(probA, probB) 
     if scoreA == 15 and scoreB == 0: 
      shutoutA = shutoutA + 1 
     if scoreA == 0 and scoreB == 15: 
      shutoutB = shutoutB + 1 

     return winsA, winsB, shutoutA, shutoutB ## The program breaks when I add 
               ## shutoutA, and shutoutB as return val            

如果任何人都可以引导我在正确的方向它将不胜感激。我得到一个ValueError：太多的值解开（预期2），当我将关闭添加到返回值。这里是整个程序：

from random import random 

def main(): 
    probA, probB, n = GetInputs() 
    winsA, winsB = simNGames(n, probA, probB) 
    PrintSummary(winsA, winsB) 


def GetInputs(): 
    a = eval(input("What is the probability player A wins the serve? ")) 
    b = eval(input("What is the probablity player B wins the serve? ")) 
    n = eval(input("How many games are they playing? ")) 
    return a, b, n 



def simNGames(n, probA, probB): 
    winsA = 0 
    winsB = 0 
    shutoutA = 0 
    shutoutB = 0 
    for i in range(n): 
     scoreA, scoreB = simOneGame(probA, probB) 
     if scoreA > scoreB: 
      winsA = winsA + 1 
     else: 
      winsB = winsB + 1 
    for i in range(n): 
     scoreA, scoreB = simOneGame(probA, probB) 
     if scoreA == 15 and scoreB == 0: 
      shutoutA = shutoutA + 1 
     if scoreA == 0 and scoreB == 15: 
      shutoutB = shutoutB + 1 

     return winsA, winsB 

def simOneGame(probA, probB): 
    serving = "A" 
    scoreA = 0 
    scoreB = 0 
    while not gameOver(scoreA, scoreB): 
     if serving == "A": 
      if random() < probA: 
       scoreA = scoreA + 1 
      else: 
       serving = "B" 

     else: 
      if random() < probB: 
       scoreB = scoreB + 1 
      else: 
       serving = "A" 
    return scoreA, scoreB 

def gameOver(a, b): 
    return a == 15 or b == 15 

def PrintSummary(winsA, winsB): 
    n = winsA + winsB 
    print("\nGames simulated:", n) 
    print("Wins for A: {0} ({1:0.1%})".format(winsA, winsA/n)) 
    print("Wins for B: {0} ({1:0.1%})".format(winsB, winsB/n)) 


if __name__ == '__main__': main() 

Answer 1

当你调用该函数：

winsA, winsB = simNGames(n, probA, probB) 

你期待的只有两个值（winsA，winsB），但返回四强。