试图解决js koan/about_array.js

我新来js和我无法解决这个问题。试图解决js koan/about_array.js

test("splice", function() { 
    var daysOfWeek = ['Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday', 'Sunday']; 
    var workingWeek = daysOfWeek.splice(__); 
    ok(workingWeek.equalTo([__]), 'what is the value of workingWeek?'); 
    ok(daysOfWeek.equalTo([__]), 'what is the value of daysOfWeek?'); 
});

我的尝试在下面，但它不工作。

test("splice", function() { 
    var daysOfWeek = ['Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday', 'Sunday']; 
    var workingWeek = daysOfWeek.splice(5,6); 
    ok(workingWeek.equalTo([5]), 'what is the value of workingWeek?'); 
    ok(daysOfWeek.equalTo([2]), 'what is the value of daysOfWeek?'); 
});

有人能给我提供任何线索吗？

来源

2013-03-21 Masato

你知道什么['splice'方法]（https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Global_Objects/Array/splice）呢？你知道'[5]'是一个数组，只有一个数字吗？ – Bergi 2013-03-21 17:57:40

你想做什么？ – ckersch 2013-03-21 17:58:10

可能的来源：https：//github.com/liammclennan/JavaScript-Koans/blob/master/topics/about_arrays.js – 2013-03-21 18:02:08

从the docs：

[该] Arraysplice方法

array.splice(index, howMany, […])

改变阵列的内容，增加新的元件，同时除去旧元素

返回[...]包含已删除元素的数组。

因此，您当前的代码将从第6个开始（索引5，即'Saturday'）删除6个元素。这有点太过分了，只删除2就足够了，尽管它在这里没有任何区别 - 它们在数组的末尾。

你proably想达到什么是

ok(workingWeek.equalTo(['Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday']), 'what is the value of workingWeek?'); 
// though it makes no practical sense, you are using splice(): 
ok(daysOfWeek.equalTo(['Saturday', 'Sunday']), 'what is the value of daysOfWeek?');

我会离开这个任务上改变参数你splice(…)电话给你:-)

来源

2013-03-21 18:16:28 Bergi

试图解决js koan/about_array.js

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