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// I'll pretend you have a #include <stdio.h> here
class A
{
virtual void func1()
{
print 0; // error!! I'll pretend this was puts("0");
}
virtual void func2()
{
print1; // error!! I'll pretend this was puts("1");
}
};
// there is a virtual table for class A. (for two virtual methods)
class B:Public A
{
void func1()
{
print2; // error!! I'll pretend this was puts("2");
}
};
// there is a virtual table for class B. (for two virtual methods)
class C:public B
{
virtual void func2()
{
print 3; // error!! I'll pretend this was puts("3");
}
}
// there is a virtual table for class C. (for two virtual methods)
int main()
{
A objA;
B* objB = new B();
C* objC = new C();
//case1:
objA = &objB; // error!! left side of type A right side of type B**
objA->func1(); // error!! operator -> on non pointer
//case2:
objA = &objC; // error!! left side of type A right side of type B**
objA->func2(); // error!! operator -> on non pointer
objA->func1(); // error!! operator -> on non pointer
return 0;
}
// nothing is printed
由于您编辑了OP代码,因此它是新版代码的答案。看评论:
#include <iostream>
using namespace std;
class A
{
virtual void func1()
{
cout << "0 " <<endl; // it's ok, but is the space supposed to be there?
}
virtual void func2()
{
cout << "1 " <<endl; // it's ok, but is the space supposed to be there?
}
};
// there is a virtual table for class A. (for two virtual methods)
class B:Public A // error!! I'll pretend Public was public (lowercase)
{
void func1()
{
cout << "2" <<endl; // it's ok, but here there's no space, is that correct?
}
};
// there is a virtual table for class B. (for two virtual methods)
class C:public B
{
virtual void func2()
{
cout << "3" <<endl; // it's ok, but here there's no space, is that correct?
}
}
// there is a virtual table for class C. (for two virtual methods)
int main()
{
A* objA;
B objB ;
C objC ;
//case1:
objA = &objB;
objA->func1(); // outputs (to stdout) a '2' (two) and whatever a
// newline is on your system (could be '\r' or '\n' or both
// or in fact anything your platform defines a newline is)
// stdout is then flushed.
//case2:
objA = &objC;
objA->func2(); // outputs (to stdout) a '3' (three) and whatever a
// newline is on your system (could be '\r' or '\n' or both
// or in fact anything your platform defines a newline is)
// stdout is then flushed.
objA->func1(); // outputs (to stdout) a '2' (two) and whatever a
// newline is on your system (could be '\r' or '\n' or both
// or in fact anything your platform defines a newline is)
// stdout is then flushed.
return 0;
}
// the output is '2' <newline> '3' <newline> '2' <newline>
// where the actual character(s) for <newline> are platform dependent
程序不编译;问的问题是学术问题。你是指'A * objA;'或'objA = * objB'和'objA = * objC'? –
首先,上面的代码甚至没有编译,所以没有输出。不要喂我们。其次,有一个精彩的文章中博士道博的,[多重继承认为是有用的(http://www.drdobbs.com/multiple-inheritance-considered-useful/184402074?pgno=1),你能看的懂如何继承和虚拟方法表工作。 –
感谢您的文章。它是一个伪代码。基本上我想知道vtable是否为B类创建? – user1687824