SQL FOR JSON转换问题

我试图运行以下查询，从示例数据库中的客户记录生成JSON字符串。SQL FOR JSON转换问题

SELECT 
    CustomerID, 
    CustomerName, 
    PersonID AS [CustomerContact.PersonID], 
    SUBSTRING(FullName, 0, CHARINDEX(' ', FullName)) AS [CustomerContact.FirstName], 
    SUBSTRING(FullName, CHARINDEX(' ', FullName) + 1, LEN(FullName)) AS [CustomerContact.LastName], 
    EmailAddress AS [CustomerContact.Email], 
    DeliveryAddressLine1 AS [CustomerContact.Address1], 
    DeliveryAddressLine2 AS [CustomerContact.Address2], 
    CityName AS [CustomerContact.City], 
    StateProvinceName AS [CustomerContact.State], 
    DeliveryPostalCode AS [CustomerContact.Zip], 
    CustomerCategoryName AS CustomerType, 
    WebsiteURL As Website 
FROM 
    Sales.Customers 
    LEFT JOIN Sales.CustomerCategories 
    ON Customers.CustomerCategoryID = CustomerCategories.CustomerCategoryID 
    LEFT JOIN Application.Cities 
    ON Customers.DeliveryCityID = Cities.CityID 
    LEFT JOIN Application.StateProvinces 
    ON Cities.StateProvinceID = StateProvinces.StateProvinceCode 
    LEFT JOIN Application.People 
    ON Customers.CustomerID = People.PersonID 
WHERE 
    Customers.CustomerID = 200 
FOR JSON PATH

当我尝试这一点，它只是引发以下错误：

Conversion failed when converting the ****** value '******' to data type ******.

有谁知道这是什么意思？

编辑：***的字面上显示为星号，而不是隐藏的值。该生产线的错误是Msg 245, Level 16, State 1, Line 1

来源

2017-04-24 user3066571

在这种情况下，这可能意味着您试图将两列用不同的类型等同。你能分享一下*****的内容吗？如果它给你一个行号？ – Simon

首先想到的是这一行：ON Cities.StateProvinceID = StateProvinces.StateProvinceCode - 你的意思是加入ID与代码？ – Simon

这实际上解决了它，它生成了JSON字符串，但它是...时髦。不是我所期望的。 – user3066571

是弹簧想到的第一件事是这一行：

ON Cities.StateProvinceID = StateProvinces.StateProvinceCode

您的意思是加入ID与代码？

来源

2017-04-24 15:51:46 Simon

SQL FOR JSON转换问题

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