显示json结果的PHP问题

Question

首先，我对PHP非常陌生，所以我仍在尝试。我的问题是：我试图在PHP中回应Bing API结果。

这里是一个JSON结果例子，这是我从

$jsonobj = json_decode($response); 

得到（的反应是我从兵得到的，所以我只粘贴了以下回应 - 万一添加此信息你不知道在哪里得到$jsonobj = json_decode($response);从）

{"d":{"results":[{"__metadata":{"uri":"https://api.datamarket.azure.com/Data.ashx/Bing/Search/Composite?Sources=\u0027web\u0027&Market=\u0027en-US\u0027&Query=\u0027php\u0027&Adult=\u0027off\u0027&$skip=0&$top=1","type":"ExpandableSearchResult"},"ID":"1c509d25-5ca4-4db5-bfc5-cafd6917e2c2","WebTotal":"10600000","WebOffset":"0","ImageTotal":"","ImageOffset":"","VideoTotal":"","VideoOffset":"","NewsTotal":"","NewsOffset":"","SpellingSuggestionsTotal":"","AlteredQuery":"","AlterationOverrideQuery":"","Web":[{"__metadata":{"uri":"https://api.datamarket.azure.com/Data.ashx/Bing/Search/ExpandableSearchResultSet(guid\u00271c509d25-5ca4-4db5-bfc5-cafd6917e2c2\u0027)/Web?$skip=0&$top=1","type":"WebResult"},"ID":"4cf2a8d6-21b7-433d-81e9-84e74091a44a","Title":"PHP: Hypertext Preprocessor","Description":"What is PHP? PHP is a widely-used general-purpose scripting language that is especially suited for Web development and can be embedded into HTML.","DisplayUrl":"www.php.net","Url":"http://www.php.net/"},{"__metadata":{"uri":"https://api.datamarket.azure.com/Data.ashx/Bing/Search/ExpandableSearchResultSet(guid\u00271c509d25-5ca4-4db5-bfc5-cafd6917e2c2\u0027)/Web?$skip=48&$top=1","type":"WebResult"},"ID":"2d8f8107-895e-4052-9edc-b656e74c3f2e","Title":"CakePHP: the rapid development php framework. Pages","Description":"Official website. Offers a manual for beginners and links towards the last version.","DisplayUrl":"cakephp.org","Url":"http://cakephp.org/"},{"__metadata":{"uri":"https://api.datamarket.azure.com/Data.ashx/Bing/Search/ExpandableSearchResultSet(guid\u00271c509d25-5ca4-4db5-bfc5-cafd6917e2c2\u0027)/Web?$skip=49&$top=1","type":"WebResult"},"ID":"816d781c-ff8b-4a60-b5b7-28d807bba28a","Title":"PHP Presents","Description":"Welcome to the PHP Presentation System. Here we list all of the available presentation categories stored within this system.","DisplayUrl":"talks.php.net","Url":"http://talks.php.net/"}],"Image":[],"Video":[],"News":[],"RelatedSearch":[],"SpellingSuggestions":[]}]}} 

现在，我明白，我可以重复，例如，WebTotal使用：

foreach($jsonobj->d->results as $value) { 
    echo $value->WebTotal; 
} 

但是，我迷失在如何回应实际结果，如Title,Description和Url。

我想：

foreach($jsonobj->d->results as $value) { 
    echo $value->Title."<br>"; 
    echo $value->Description."<br>"; 
    echo $value->Url."<br>"; 
} 

也类似：

foreach($jsonobj->d->results->Web as $value) { 
    echo $value->Title."<br>"; 
    echo $value->Description."<br>"; 
    echo $value->Url."<br>"; 
} 

，因为我认为添加Web到foreach将可能呼应正确的价值观，但没有成功。

也许有人可以帮助我，告诉我我做错了什么？

我的任务将有如下结果：

标题：PHP：Hypertext Preprocessor的

描述：PHP是什么？ PHP是一种广泛使用的通用 脚本语言，特别适合Web开发，并且 可以嵌入到HTML中。

的URL：http：//www.php.net/

然后，其他两个结果。

太谢谢你了:)

Answer 1

你可以做到这一点，如下所示：

foreach($jsonobj->d->results as $result) { 
    foreach($result->Web as $value) { 
     echo $value->Title; 
     // and the same for the other properties 
    } 
} 

通过方式：你应该使用一个工具来格式化你的json字符串。通过这种方式，json数据将如何变得更加清晰。

Answer 2

results包含数组，所以你需要的东西是这样的：

foreach($jsonobj->d->results[0]->Web as $value) 
{ 
    echo 'Title: ' . $value->Title . '<br /><br />'; 
    echo 'Description: ' . $value->Description . '<br /><br />'; 
    echo 'Url: ' . $value->Url . '<br /><br /><br />'; 
} 

Answer 3

首先使用print_r方法，这样你就可以看到对象是怎么样的，所以你可以确定从哪里开始循环。

echo '<pre>'; 
print_r($jsonobj); 

然后将类型更改为像数组$ array =（array）$ jsonobj;所以你可以用它来array_shift功能（你可以使用此功能调整阵列）

http://php.net/manual/en/function.array-shift.php