排序根据另一单元阵列

Question

我有两个单元阵列的单元阵列，

reference = [{'A'}, {'B'}, {'H'}, {'D'}, {'G'}]; 
array2 = [{'A'}, {'G'}, {'H'}, {'B'}, {'D'}]; 

是否有MATLAB任何智能方式来排序数组2，相对于所述单元阵列的参考;

该函数应该返回array2的索引，其顺序与“reference”的顺序相同（array2将与参考相同）。

为如

magic_order = function(array2, reference) 
.... 
end 

magic_order（数组2，参考）将返回

1,4,3,5,2 

，现在，如果我做

array2(1,4,3,5,2) 

我会得到相同的参考

排序功能

reference = [{'A'}, {'B'}, {'H'}, {'D'}, {'G'}]; 
array2 = [{'A'}, {'G'}, {'H'}, {'B'}, {'D'}]; 
[a, b] = sort(reference) 
isequal(reference, array2(b)) 
ans = 0 

Answer 1

ismember的第二个输出也可能有用。

reference = [{'A'}, {'B'}, {'H'}, {'D'}, {'G'}]; 
array2 = [{'A'}, {'G'}, {'H'}, {'B'}, {'D'}]; 
[~, pos] = ismember(reference,array2); 

结果：

>> isequal(array2(pos),reference) 

ans = 

    1 

Answer 2

使用intersect：

reference = [{'A'}, {'B'}, {'H'}, {'D'}, {'G'}]; 
array2 = [{'A'}, {'G'}, {'H'}, {'B'}, {'D'}]; 

[~, ~, idx] = intersect(reference, array2, 'stable'); 

将返回：

>> isequal(reference, array2(idx)) 

ans = 

    1 

的使用setOrder='stable'intersect（我已经忽略不计）的第一输出，返回共同的价值观reference和array2的顺序与相同。第三个输出是第一个输出中的array2索引。假设单元阵列相等，这将是reference中array2的索引。