2017-03-06 45 views
2

我正在编写重命名报告并将它们放入文件夹的脚本。按文件名重命名报告

报告名称必须更改为正确的日期(日期必须在文件名中)。

例如我有一个名为“Report_2015_02”的报告/我必须从文件名减去一个月 - 而不是系统时间

在这种情况下,新的报告名称必须是“Report_2015_01”

但在我使用SYSTEMTIME的瞬间,所以REPORTNAME将是“Report_2017_02”因为SYSTEMTIME(2017_03)减去一个月的2017_02。 ..

问:如何使用文件名的日期而不是系统时间?

这里是我的代码:

#today's date (year-month-day) 
$todaydate = Get-Date -Format yyyy-MM-dd 

#arrays (today => systemtime) 
$todaydate = $todaydate.Split('-') 
$todaydate[0] #year 
$todaydate[1] #month 
$todaydate[2] #day 

#arrays yesterday (systemtime - one day) 
$yesterdaysdate = Get-Date((Get-Date).AddDays(-1)) -Format yyyy-MM-dd 
$yesterdaysdate = $yesterdaysdate.Split('-') 
$yesterdaysdate[0] #year 
$yesterdaysdate[1] #month 
$yesterdaysdate[2] #day 

#arrays yesterday (systemtime - one day) 
$lastmonth = Get-Date((Get-Date).AddMonths(-1)) -Format yyyy-MM-dd 
$lastmonth = $lastmonth.Split('-') 
$lastmonth[0] #year 
$lastmonth[1] #month 
$lastmonth[2] #day 

#Example 1: Filename "Report_Telephone_yyyy-mm" => in this case "Report_Telephone_2016-12" 
#it renames the file -> minus one month, so the name must be "Report_Telephone_2016-11" 
$filename='Report_Telephone_'+ $lastmonth[0]+'-'+ $lastmonth[1] + '.xlsx' 

write-host $filename 
rename-item 'c:\Reporting\Report_Telephone_' + $todaydate[0] +'-' + $todaydate[1] + '.xlsx' -NewName $filename 

$sourcepath='C:\Reporting\'+ $filename 
write-host $sourcepath 
$destinationpath='C:\Reporting\'+ $lastmonth[0]+'\'+ $lastmonth[1] 
write-host $destinationpath 
if(test-path $destinationpath) 
{ 

} 
else 
{ 
    mkdir $destinationpath 
} 
move-item -path $sourcepath -destination $destinationpath 



#Example 2: Filename "Report_Outlook_yyyy-mm-dd" => in this case "Report_Outlook_2016-12-14" 
#it renames the file -> minus one day, so the name must be "Report_Outlook_2016-12-13" 

$filename='Report_Outlook_'+ $lastmonth[0]+'-'+ $lastmonth[1] + '.xlsx' 

write-host $filename 
rename-item 'c:\Reporting\Report_Outlook_' + $todaydate[0] +'-' + $todaydate[1] + '.xlsx' -NewName $filename 

$sourcepath='C:\Reporting\'+ $filename 
write-host $sourcepath 
$destinationpath='C:\Reporting\'+ $yesterdaysdate[0]+'\'+ $yesterdaysdate[1] 
write-host $destinationpath 
if(test-path $destinationpath) 
{ 

} 
else 
{ 
    mkdir $destinationpath 
} 
move-item -path $sourcepath -destination $destinationpath 



#that is just for generating log-files 
[System.IO.File]::WriteAllText("$sourcepath\Protokoll_$todaydate.xls", $output) 

回答

1

您可以使用一个简单的正则表达式抢月份,它为一个整数,。减去 1,最后格式它作为一个字符串小数点后两位:

$fileName = 'Report_2015_02' # Probably want to use Get-ChildItem here... 
$fileMonth = [int][regex]::Match($fileName, '\w+_\d+_(\d+)').Groups[1].Value 
$fileMonth = "{0:D2}" -f ($fileMonth - 1)