Bash if/else循环错误

Question

正如标题所述。如果在Bash中声明简单。我一直在试图弄清为什么这个循环不起作用，现在我还没有拿出任何东西两天。洞察力将不胜感激。

declare -r TIMESTAMP=$(date "+%Y-%m-%d %H:%M:%S,%3N") 

CHECK="$(grep -c "$TIMESTAMP" /var/log/host/logname.log)" 
if [ "$CHECK" -eq 0 ] 
then 
    COLOR="green" 
elif [ 0 -lt "$CHECK" ] && [ "$CHECK" -le 5 ] 
    COLOR="yellow" 
else 
    COLOR="red" 
fi 

COLOR var是由我正在使用的系统预设的东西。红色/黄色/绿色都是正确的，但是我的语法或逻辑都是问题，尽管我一直在努力确定。谢谢！

编辑：我的错。清晨和问题充满了错字。我修好了他们。错误如下，

syntax error near unexpected token `else' 
`  else' 

Answer 1

你有一些错误，这可能有助于

declare -r TIMESTAMP=$(date "+%Y-%m-%d %H:%M:%S,%3N") 
CHECK="$(grep -c "$TIMESTAMP" /var/log/host/logname.log)" 
if [ "$CHECK" -eq 0 ] 
then 
    COLOR="green" 
elif [ 0 -lt "$CHECK" ] && [ "$CHECK" -le 5 ] 
then 
    COLOR="yellow" 
else 
    COLOR="green" 
fi 

Answer 2

你忘了报价，和然后。

declare -r TIMESTAMP=$(date "+%Y-%m-%d %H:%M:%S,%3N") # missing " here 

CHECK="$(grep -c "$TIMESTAMP" /var/log/host/logname.log)" 
if [ "$CHECK" -eq 0 ]; then 
    COLOR="green" 
elif [ 0 -lt "$CHECK" ] && [ "$CHECK" -le 5 ]; then # missing then was here 
    COLOR="yellow" 
else 
    COLOR="red" 
fi