在PHP中存储具有不同值和名称的多个复选框MYSQLI

-2

在PHP MYSQLI中存储具有不同值和名称的多个复选框时出现问题。我已经成功地用单列和单列，但是当存储3列时它失败了。在PHP中存储具有不同值和名称的多个复选框MYSQLI

处理过程：当某人选择department,position和location并带有多个复选框时，它将根据id_user在每行和每列存储到db。

我的表：

id, id_usr, id_department, id_position, id_location

我想要的结果：

1 | 1 | 4 | 2 | 2 

2 | 1 | 1 | 2 | 1 

3 | 1 | 2 | 3 | 4 

4 | 1 | 4 | 2 | 2 

5 | 2 | 1 | 2 | 1 

6 | 2 | 2 | 3 | 4

我的代码：

<div class="form-group"><label>Department</label><br> 
    <?php 
    $department = "SELECT * FROM loker_department ORDER BY nama_department"; 
    $result = mysqli_query($conn, $department); 
    if (mysqli_num_rows($result) > 0) 
    { 
    while ($data = mysqli_fetch_array($result)) 
    { 
     echo "<input type='checkbox' name='department[]' value='".$data['id_department']."'/> $data[nama_department]<br>"; 
    } 
    }else{echo "No data";} 
    ?> 
</div> 
<div class="form-group"><label>Position</label><br> 
    <?php 
    $position = "SELECT * FROM loker_position ORDER BY nama_position"; 
    $result = mysqli_query($conn, $position); 
    if (mysqli_num_rows($result) > 0) 
    { 
    while ($data = mysqli_fetch_array($result)) 
    { 
     echo "<input type='checkbox' name='position[]' value='".$data['id_position']."'/> $data[nama_position]<br>"; 
    } 
    }else{echo "No data";} 
    ?> 
</div> 
<div class="form-group"><label>Location</label><br> 
    <?php 
    $location = "SELECT * FROM loker_location ORDER BY nama_location"; 
    $result = mysqli_query($conn, $location); 
    if (mysqli_num_rows($result) > 0) 
    { 
    while ($data = mysqli_fetch_array($result)) 
    { 
     echo "<input type='checkbox' name='location[]' value='".$data['id_location']."'/> $data[nama_location]<br>"; 
    } 
    }else{echo "No data";} 
    ?> 
</div> 

$department = $_POST['department']; 
$position = $_POST['position']; 
$location = $_POST['location']; 

foreach($department as $departments && $position as $positions && $location as $locations) 
{ 
    $create = "INSERT INTO loker_user_subsc (id_department,id_position,id_location) VALUES ('$departments','$positions','$locations')"; 
    $result5 = mysqli_query($conn, $create); 
}

任何帮助/ soluti ons将不胜感激。

来源

2017-01-01 azmi27

错误，您在使用http://php.net/manual/en/function.error-reporting得到什么。 PHP和http://php.net/manual/en/mysqli.error.php？ –

'foreach'获取一个数组中的所有值;你应该得到一个关于它的错误。看到这个问答http://stackoverflow.com/questions/4480803/two-arrays-in-foreach-loop –

@ Fred-ii-解析错误：语法错误，意外'&&'（T_BOOLEAN_OR），期待'）'在 – azmi27

-1

foreach($department as $departments && $position as $positions && $location as $locations) 
{ 
    $create = "INSERT INTO loker_user_subsc (id_department,id_position,id_location) VALUES ('$departments','$positions','$locations')"; 
    $result5 = mysqli_query($conn, $create); 
}

看到后，我很快就引用php.net foreach documentation并确认我的直觉是你给的参数错误

你shud通过AT A TIME到的foreach 一个阵列，而不是与参加一切。

分离的阵列，以最低的，使用不同的foreach语句，然后你可能认为重构

来源

2017-01-02 00:38:01 funsholaniyi

在PHP中存储具有不同值和名称的多个复选框MYSQLI

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