Python - 如何查找日期时间重叠？

-2

我已经持续时间表示为一对datetime对象的这样Python - 如何查找日期时间重叠？

(datetime(2014, 1, 23, 14, 49, 6, 185955), datetime(2015, 4, 18, 14, 49, 6, 185955))

我有这样

[(datetime(2014, 1, 23, 14, 49, 6, 185955), datetime(2015, 4, 18, 14, 49, 6, 185955)), (datetime(2015, 2, 2, 14, 49, 6, 185955), datetime(2015, 10, 23, 14, 49, 6, 185955)),]

现在我怎样计算的（小时方面的重叠的持续时间这样的元组的列表，分，秒）列表中的所有持续时间（这里是一对日期时间对象）？

E.g：

A  C    B   D G E   H I  J F 
|-----------------------| 
     |--------------------------| 
              |-----------------------| 
             |--------------| |-----|

这里AB，CD是对datetime对象的。在列表中，如何在（小时，分钟，秒）方面获得重叠CB？

来源

2015-10-23 Tejaswini Reddy

有可能什么你已经尝试过自己，你可以与我们分享？如果它不起作用，那很好，那么我们可以看看如何改进它 –

那么只需从B中减去C？尝试这个。 – Noxeus

试试这个：

from datetime import datetime 
t = [(datetime(2014, 1, 23, 14, 49, 6, 185955), datetime(2015, 4, 18, 14, 49, 6, 185955)), (datetime(2015, 2, 2, 14, 49, 6, 185955), datetime(2015, 10, 23, 14, 49, 6, 185955))] 
def time_overlap(t): 
    overlap = (min(t[0][1], t[1][1]) - max(t[0][0], t[1][0])) 
    days = overlap.days+1 
    hours, remainder = divmod(overlap.seconds, 3600) 
    minutes, seconds = divmod(remainder, 60) 
    hours += days*24 
    return (hours,minutes,seconds) 
print(time_overlap(t))

输出：

(1824, 0, 0)

要找到多个日期时间重叠，这样做：

from datetime import datetime 
t = [(datetime(2014, 1, 23, 14, 49, 6, 185955), datetime(2015, 4, 18, 14, 49, 6, 185955)), (datetime(2015, 2, 2, 14, 49, 6, 185955), datetime(2015, 10, 23, 14, 49, 6, 185955))] 
def time_overlap(t): 
    overlap = (min([x[1] for x in t]) - max([x[0] for x in t])) 
    days = overlap.days+1 
    hours, remainder = divmod(overlap.seconds, 3600) 
    minutes, seconds = divmod(remainder, 60) 
    hours += days*24 
    return (hours,minutes,seconds) 
print(time_overlap(t))

来源

2015-10-23 10:24:51

Python - 如何查找日期时间重叠？

回答

相关问题