我想根据另一个文件的顺序对两列文件进行排序。使用以下命令:bash shell脚本中的awk错误
awk 'FNR == NR {lineno[$1] = NR; next} {print lineno[$1], $0;}' associativity4Way_cacheSize32KB_replacementPolicy1.outs associativity4Way_cacheSize32KB_replacementPolicy2.outs | sort -k 1,1n | cut -d " " -f2- > sorted
当我在外壳上使用AWK命令时,它工作正常。下面是我的文件头内容和输出:
这是“associativity4Way_cacheSize32KB_replacementPolicy2.outs”
LONG_MOBILE-10.bt9.trace.gz_a4_b64_c32 4.516192
LONG_MOBILE-10.bt9.trace.gz_a4_b64_c32 4.147467
LONG_MOBILE-10.bt9.trace.gz_a4_b64_c64 2.040121
LONG_MOBILE-10.bt9.trace.gz_a4_b64_c64 1.837639
LONG_MOBILE-10.bt9.trace.gz_a4_b64_c64 3.068701
LONG_MOBILE-11.bt9.trace.gz_a4_b64_c32 0.474358
LONG_MOBILE-11.bt9.trace.gz_a4_b64_c32 0.545525
LONG_MOBILE-11.bt9.trace.gz_a4_b64_c32 0.469907
LONG_MOBILE-11.bt9.trace.gz_a4_b64_c64 0.19461
...
团长,这是“ssociativity4Way_cacheSize32KB_replacementPolicy1.outs”
SHORT_SERVER-2.bt9.trace.gz_a4_b64_c32 29.869599
SHORT_SERVER-2.bt9.trace.gz_a4_b64_c32 29.100611
SHORT_SERVER-2.bt9.trace.gz_a4_b64_c32 29.068284
SHORT_SERVER-2.bt9.trace.gz_a4_b64_c32 28.559002
SHORT_MOBILE-20.bt9.trace.gz_a4_b64_c32 21.332859
SHORT_MOBILE-22.bt9.trace.gz_a4_b64_c32 20.605805
SHORT_MOBILE-20.bt9.trace.gz_a4_b64_c32 20.256246
SHORT_MOBILE-20.bt9.trace.gz_a4_b64_c32 20.193713
SHORT_MOBILE-22.bt9.trace.gz_a4_b64_c32 20.119883
SHORT_MOBILE-22.bt9.trace.gz_a4_b64_c32 20.099358
...
输出排序完美如我所愿:
SHORT_SERVER-2.bt9.trace.gz_a4_b64_c32 28.559002
SHORT_SERVER-2.bt9.trace.gz_a4_b64_c32 29.068284
SHORT_SERVER-2.bt9.trace.gz_a4_b64_c32 29.100611
SHORT_SERVER-2.bt9.trace.gz_a4_b64_c32 29.869599
SHORT_MOBILE-20.bt9.trace.gz_a4_b64_c32 20.193713
SHORT_MOBILE-20.bt9.trace.gz_a4_b64_c32 20.256246
SHORT_MOBILE-20.bt9.trace.gz_a4_b64_c32 21.332859
...
T他的问题出现时,我尝试把awk命令我bash脚本里面能够做到这一点的其他文件:
set lru = "associativity${a}Way_cacheSize${c}KB_replacementPolicy1.outs"
set policy = "associativity${a}Way_cacheSize${c}KB_replacementPolicy${r}.outs"
awk "FNR == NR {lineno["$policy"] = NR; next} {print lineno["$policy"], "$lru";}" "$lru" "$policy" | sort -k 1,1n | cut -d " " -f2- > "${policy}_sorted"
这是错误我得到:
awk: cmd. line:1: FNR == NR {lineno[associativity4Way_cacheSize32KB_replacementPolicy3.outs] = NR; next} {print lineno[associativity4Way_cacheSize32KB_replacementPolicy3.outs], associativity4Way_cacheSize32KB_replacementPolicy1.outs;}
awk: cmd. line:1: ^syntax error
我也试过这个(这里提供了一个答案),但输出不正确。它在输出文件中多次打印'lru'文件的名称。
set lru = "associativity${a}Way_cacheSize${c}KB_replacementPolicy1.outs"
set policy = "associativity${a}Way_cacheSize${c}KB_replacementPolicy${r}.outs"
awk -v policy="$policy" -v lru="$lru" 'FNR == NR {lineno[policy] = NR; next} {print lineno[policy], lru}' "$lru" "$policy" | sort -k 1,1n | cut -d ' ' -f2- > "${policy}_sorted"
associativity8Way_cacheSize64KB_replacementPolicy1.outs
associativity8Way_cacheSize64KB_replacementPolicy1.outs
associativity8Way_cacheSize64KB_replacementPolicy1.outs
associativity8Way_cacheSize64KB_replacementPolicy1.outs
associativity8Way_cacheSize64KB_replacementPolicy1.outs
associativity8Way_cacheSize64KB_replacementPolicy1.outs
associativity8Way_cacheSize64KB_replacementPolicy1.outs
associativity8Way_cacheSize64KB_replacementPolicy1.outs
associativity8Way_cacheSize64KB_replacementPolicy1.outs
associativity8Way_cacheSize64KB_replacementPolicy1.outs
有人能告诉我这里错了吗?
您是否尝试设置文件的完整路径? –
使用编辑器的{}}按钮编辑您的问题,以正确地格式化您的代码,以便我们知道您的代码的真实外观。空白区域在awk脚本中很重要。 –
@James:是的,我也尝试了完整的路径。仍然是同样的问题。 – samira