如何在熊猫中将数据分成不同的变量

Question

嗨，我有一个看起来像这样的数据train.dat。我试图创建一个变量，它将包含包含（-1或1）的列的[ith]值，以及另一个变量来保存包含字符串的列的值。

到目前为止，我已经试过了，

df=pd.read_csv("train.dat",delimiter="\t", sep=',') 
# print(df.head()) 


# separate names from classes 
vals = df.ix[:,:].values 
names = [n[0][3:] for n in vals] 
cls = [n[0][0:] for n in vals] 
print(cls) 

但是输出看起来都混乱了，任何帮助，将不胜感激。我在python

Answer 1

一个begineer如果数值之后的字符是一个标签，你没事，所有你需要的

import io # using io.StringIO for demonstration 
import pandas as pd 

ratings = "-1\tThis movie really sucks.\n-1\tRun colored water through 
a reflux condenser and call it a science movie?\n+1\tJust another zombie flick? You'll be surprised!" 

df = pd.read_csv(io.StringIO(ratings), sep='\t', 
       header=None, names=['change', 'rating']) 

• 传递header=None可以确保第一行是解释为数据。
• 传递names=['change', 'rating']提供了一些（合理的）列标题。

当然，该字符不是一个选项卡：D。

import io # using io.string 
import pandas as pd 

ratings = "-1 This movie really sucks.\n-1 Run colored water through a 
reflux condenser and call it a science movie?\n+1 Just another zombie 
flick? You'll be surprised!" 

df = pd.read_csv(io.StringIO(ratings), sep='\t', 
       header=None, names=['stuff']) 

df['change'], df['rating'] = df.stuff.str[:3], df.stuff.str[3:] 
df.drop('stuff', axis=1) 

一个可行的选择是将整个评分读作一个临时列，拆分字符串，将其分配到两列并最终删除临时列。