7
我不能为了我的生活找出这条SQL语句有什么问题,以及为什么它没有产生任何结果。如果我将LEFT JOIN取出是有效的,那么它有什么问题?用LEFT JOIN嵌套的SELECT语句
SELECT b.id, r.avg_rating
FROM items AS b
LEFT JOIN
(
SELECT avg(rating) as avg_rating
FROM ratings
GROUP BY item_id
) AS r
ON b.id = r.item_id
WHERE b.creator = " . $user_id . "
AND b.active = 1
AND b.deleted = 0
ORDER BY b.order ASC, b.added DESC
希望大大的帮助。
是啊,谢谢你的SQL大师约翰!我会在12分钟内接受你的回答! – Wasim