嵌套mysql的select语句

Question

我有如下的查询：

$sult = mysql_query("select * from stories where `categ` = 'businessnews' and `stryid`='".mysql_query("SELECT * FROM comments WHERE `comto`='".mysql_query("select * from stories where `categ` ='businessnews'")." ORDER BY COUNT(comto) DESC")."' LIMIT 3") or die(mysql_error()); 
       while($ow=mysql_fetch_array($sult)){ 

上面的代码应该返回顶部3“故事”最意见{计数（comto）}。评论存储在与故事不同的表格中。上面的代码不会返回任何值，也不会显示任何错误。有人可以帮忙吗？

Answer 1

你传入查询MySQL服务器，以便让它做其工作。

SELECT 
    *, 
    (SELECT COUNT(1) FROM comments WHERE `comto` = WHERE story_id = s.id) as commentsCount 
FROM stories s 
WHERE 
    s.categ = 'businessnews' 
ORDER BY commentsCount DESC 
LIMIT 3 

Answer 2

使用子查询这项工作... http://dev.mysql.com/doc/refman/5.0/en/subqueries.html