提取并绘制使用Python 3

Question

为了清楚的目的而列出的明文数据我已创建包含数据的格式的一个例子的要旨我指的是：

https://gist.github.com/TestAcc7777/5823760

经过一些其他不相关的数据，输出文件包含许多这些表格块，一个接一个地排列，并且每次都重复标题部分。每个标题实例最多有8组读数，它们一起组成一个块。标题中数量的组织反映了后续读数值的组织。

鉴于这一点，我需要提取标题中给出的一些数量的值，将它们放入一个文件及其相关数量，并且让matplotlib绘制一组数量与另一组数量的关系。例如eng_tot与时间（ps）。

我完全失去了，因为这完全落在了我使用Python或matplotlib的经验之外，所以任何帮助都是值得欢迎的。

Answer 1

这不是一个完整的答案，但它应该让你开始。

#!/bin/env python 

import sys 
import re 
import pprint 

# Some function that determines whether a line is a seperator 
def is_sep(line): 
    return (line.count('-') > 80) 

# Some function that parses the "block" 
def parse_block(lines): 
    parsed_lines = [] 
    for line in lines: 
     matches = re.findall('(\S+)', line) 
     parsed_lines.append(matches) 
    return parsed_lines 

if __name__ == "__main__": 
    # Read in data 
    with open('data.txt', 'r') as fh: 
     data = fh.read() 

    # Split data into lines, then split the lines into "blocks" 
    blocks = [] 
    block_lines = [] 
    for line in data.splitlines(): 
     if(is_sep(line)): 
      blocks.append(block_lines) 
      block_lines = [] 
     else: 
      block_lines.append(line) 

    # This splitting method will create an empty "block" as the first element of the list, delete it 
    blocks = blocks[1:] 

    # For all blocks but the header block, pass it to "parse_block" 
    parsed_blocks = [] 
    for block in blocks[1:]: 
     parsed_blocks.append(parse_block(block)) 

    pprint.pprint(parsed_blocks[0]) 

例如，您的数据的最后一个块会被解析为：

[['1', '2.6814E+03', '3.3117E+02', '1.6616E+03', '-1.1814E+02', '1.8312E+03', '3.5247E+03', '2.5879E+02', '-3.8350E+03', '0.0000E+00'], 
['0.0', '2.5785E+04', '6.8687E+01', '-6.7273E+04', '-7.6310E+03', '-1.8316E+03', '-5.7811E+04', '0.0000E+00', '0.0000E+00', '0.0000E+00'], 
['4.9', '1.3300E+04', '0.0000E+00', '0.0000E+00', '0.0000E+00', '9.0000E+01', '9.0000E+01', '9.0000E+01', '0.0000E+00', '1.1911E+02'], 
[], 
['rolling', '2.6814E+03', '3.3117E+02', '1.6616E+03', '-1.1814E+02', '1.8312E+03', '3.5247E+03', '2.5879E+02', '-3.8350E+03', '0.0000E+00'], 
['averages', '2.5785E+04', '6.8687E+01', '-6.7273E+04', '-7.6310E+03', '-1.8316E+03', '-5.7811E+04', '0.0000E+00', '0.0000E+00', '0.0000E+00'], 
['1.3300E+04', '0.0000E+00', '0.0000E+00', '0.0000E+00', '9.0000E+01', '9.0000E+01', '9.0000E+01', '0.0000E+00', '1.1911E+02']]