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我创建了一个使用弹簧安全登录的简单项目。 我的项目组成由截图提供：无法使用弹簧安全登录
。
波纹管是将所需的文件：
弹簧security.xml文件
<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/security"
\t xmlns:beans="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
\t xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/security
http://www.springframework.org/schema/security/spring-security.xsd">
\t <http auto-config="true">
\t \t <intercept-url pattern="/welcome.jsf" access="ROLE_USER" />
\t \t <form-login login-page="/login.jsf" default-target-url="/welcome.jsf"
\t \t \t authentication-failure-url="/login.jsf?status=error" />
\t \t <logout logout-success-url="/login.jsf?status=logout" />
\t </http>
\t <authentication-manager>
\t \t <authentication-provider>
\t \t \t <user-service>
\t \t \t \t <user name="walid" password="111" authorities="ROLE_USER" />
\t \t \t </user-service>
\t \t </authentication-provider>
\t </authentication-manager>
</beans:beans>的web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web_1:web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
\t \t \t \t xmlns="http://java.sun.com/xml/ns/j2ee"
\t \t \t \t xmlns:javaee="http://xmlns.jcp.org/xml/ns/javaee"
\t \t \t \t xmlns:web="http://xmlns.jcp.org/xml/ns/javaee"
\t \t \t \t xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
\t \t \t \t \t \t \t \t \t http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd
\t \t \t \t \t \t \t \t \t http://java.sun.com/xml/ns/j2ee
\t \t \t \t \t \t \t \t \t http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd
\t \t \t \t \t \t \t \t \t http://xmlns.jcp.org/xml/ns/javaee
\t \t \t \t \t \t \t \t \t http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
\t \t \t \t id="Spring-Security-Custom-Login-Form_ID"
\t \t \t \t version="2.4">
<javaee:display-name>HelloWorld</javaee:display-name>
<javaee:listener>
<javaee:listener-class>org.springframework.web.context.ContextLoaderListener</javaee:listener-class>
</javaee:listener>
<javaee:filter>
<javaee:filter-name>springSecurityFilterChain</javaee:filter-name>
<javaee:filter-class>org.springframework.web.filter.DelegatingFilterProxy</javaee:filter-class>
</javaee:filter>
<javaee:filter-mapping>
<javaee:filter-name>springSecurityFilterChain</javaee:filter-name>
<javaee:url-pattern>/*</javaee:url-pattern>
</javaee:filter-mapping>
<javaee:context-param>
<javaee:param-name>contextConfigLocation</javaee:param-name>
<javaee:param-value>/WEB-INF/spring-security.xml</javaee:param-value>
</javaee:context-param>
<javaee:context-param>
<javaee:description>State saving method: 'client' or 'server' (=default). See JSF Specification 2.5.2</javaee:description>
<javaee:param-name>javax.faces.STATE_SAVING_METHOD</javaee:param-name>
<javaee:param-value>client</javaee:param-value>
</javaee:context-param>
<javaee:context-param>
<javaee:param-name>javax.servlet.jsp.jstl.fmt.localizationContext</javaee:param-name>
<javaee:param-value>resources.application</javaee:param-value>
</javaee:context-param>
<javaee:listener>
<javaee:listener-class>com.sun.faces.config.ConfigureListener</javaee:listener-class>
</javaee:listener>
<javaee:servlet>
<javaee:servlet-name>Faces Servlet</javaee:servlet-name>
<javaee:servlet-class>javax.faces.webapp.FacesServlet</javaee:servlet-class>
<javaee:load-on-startup>1</javaee:load-on-startup>
</javaee:servlet>
<javaee:servlet-mapping>
<javaee:servlet-name>Faces Servlet</javaee:servlet-name>
<javaee:url-pattern>/faces/*</javaee:url-pattern>
</javaee:servlet-mapping>
</web_1:web-app>login.xhtml
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml"
\t xmlns:c="http://java.sun.com/jstl/core">
<body>
\t <h3>Enter your username and password</h3>
\t <form method="post" action="j_spring_security_check">
\t \t UserName :<input name="j_username" type="text" /> <br />
\t \t Password :<input name="j_password" type="password" /> <br />
\t \t <input value="Login" type="submit" />
\t </form>
\t
\t <br />
\t <c:if test="${param.status=='error'}">
\t \t <label style="color:red">Invalid username or password!!</label>
\t </c:if>
\t <c:if test="${param.status=='logout'}">
\t \t <label style="color:red">Logged out successfully!</label>
\t </c:if>
</body>
</html>welcome.xhtml
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<body>
\t <h2>Welcome Page</h2>
\t <br />
\t <a href="j_spring_security_logout"> Logout </a>
</body>
</html>与（瓦利德111）登录后，我得到了this exception 你能帮我解决这个。非常感谢。
