嗨,我想把我的应用程序登录页面。 我的login.jsp是弹簧安全2.0.7和弹簧2.5的登录表单问题
<form name='f' action="<c:url value='j_spring_security_check' />"
method='POST'>
<table>
<tr>
<td>User:</td>
<td><input type='text' name='j_username' value=''>
</td>
</tr>
<tr>
<td>Password:</td>
<td><input type='password' name='j_password' />
</td>
</tr>
<tr>
<td colspan='2'><input name="submit" type="submit"
value="submit" />
</td>
</tr>
<tr>
<td colspan='2'><input name="reset" type="reset" />
</td>
</tr>
</table>
</form>
</body>
</html>
登录控制器
@Controller 公共类的LoginController {
@RequestMapping("/user/login.do")
public ModelAndView handleLoginForm(HttpServletRequest request) {
String errParam = request.getParameter("error");
ModelAndView mv = new ModelAndView("login");
if(errParam != null) {
mv.addObject("error", "Benutzer oder Kennwort unzulässig");
}
return mv;
}
}
春天secuirty XML
<http auto-config="true">
<intercept-url pattern="/login"
access="ROLE_USER" />
<intercept-url pattern="/j_spring_security_check"
access="ROLE_USER" />
<form-login login-page="/login"
login-processing-url="/j_spring_security_check" default-target-url="/userPage.do"
authentication-failure-url="/login?error=1" />
<logout logout-success-url="/login"
logout-url="/logout" />
<!-- <intercept-url pattern="/user/userPage.do" access="ROLE_USER" />
<form-login login-page="/user/login.do" default-target-url="/user/userPage.do"
authentication-failure-url="/loginfailed" />
<logout logout-success-url="/logout" /> -->
</http>
<authentication-provider>
<user-service id="userDetailsService">
<user name="admin" password="admin" authorities="ROLE_USER, ROLE_ADMIN" />
<user name="username" password="password" authorities="ROLE_USER" />
<user name="test" password="test" authorities="ROLE_USER" />
</user-service>
</authentication-provider>
</beans:beans>
的Spring XML
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE beans PUBLIC "-//SPRING//DTD BEAN//EN" "http://www.springframework.org/dtd/spring-beans.dtd">
<beans>
<bean id="userFormValidator" class="com.validator.UserFormValidator"/>
<bean id="userProxy"
class="org.springframework.aop.framework.ProxyFactoryBean">
<property name="target" ref="userManager" />
<property name="interceptorNames">
<list>
<value>transactionInterceptor</value>
</list>
</property>
</bean>
<bean id="genderManager" class="com.service.impl.GenderManagerImpl">
</bean>
<bean id="userProxyBean" class="org.springframework.aop.framework.ProxyFactoryBean">
<property name="proxyInterfaces">
<value>com.service.UserManager</value>
</property>
<property name="target">
<ref bean="userManager" />
</property>
<property name="interceptorNames">
<list>
<value>loggerAdviser</value>
</list>
</property>
</bean>
<bean id="genderProxyBean" class="org.springframework.aop.framework.ProxyFactoryBean">
<property name="proxyInterfaces">
<value>com.service.GenderManager</value>
</property>
<property name="target">
<ref bean="genderManager" />
</property>
<property name="interceptorNames">
<list>
<value>loggerAdviser</value>
</list>
</property>
</bean>
<bean id="loggerAdviser" class="org.springframework.aop.support.RegexpMethodPointcutAdvisor">
<property name="advice">
<ref bean="loggingInterceptor"/>
</property>
<property name="patterns">
<value>.*</value>
</property>
</bean>
<bean id="loggingInterceptor" class="com.log.LoggingInterceptor"/>
<bean id="userDetailController" class="com.web.UserDetailController">
<property name="userManager"><ref bean="userProxyBean"/></property>
</bean>
<bean id="loginController" class="com.web.LoginController">
</bean>
<bean id="userController" class="com.web.UserController">
<property name="sessionForm"><value>true</value></property>
<property name="commandName"><value>userBean</value></property>
<property name="commandClass"><value>com.beans.UserBean</value></property>
<property name="validator"><ref bean="userFormValidator"/></property>
<property name="formView"><value>userForm</value></property>
<property name="successView"><value>userDetail.do</value></property>
<property name="userManager"><ref bean="userProxyBean"/></property>
<property name="genderManager"><ref bean="genderProxyBean"/></property>
</bean>
<bean id="urlMapping" class="org.springframework.web.servlet.handler.SimpleUrlHandlerMapping">
<property name="urlMap">
<map>
<entry key="/user/userPage.do"><ref bean="userController"/></entry>
<entry key="/user/userDetail.do"><ref bean="userDetailController"/></entry>
<entry key="/user/login.do"><ref bean="loginController"/></entry>
</map>
</property>
</bean>
<bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="viewClass"><value>org.springframework.web.servlet.view.JstlView</value></property>
<property name="prefix"><value>/WEB-INF/jsp/</value></property>
<property name="suffix"><value>.jsp</value></property>
</bean>
</beans>
的web.xml
<servlet>
<servlet-name>context</servlet-name>
<servlet-class>
org.springframework.web.context.ContextLoaderServlet
</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<!-- Spring context loading ends-->
<servlet>
<servlet-name>user</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>user</servlet-name>
<url-pattern>*.do</url-pattern>
</servlet-mapping>
<servlet>
<servlet-name>dwr-invoker</servlet-name>
<servlet-class>uk.ltd.getahead.dwr.DWRServlet</servlet-class>
<load-on-startup>2</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dwr-invoker</servlet-name>
<url-pattern>/dwr/*</url-pattern>
</servlet-mapping>
<taglib>
<taglib-uri>/spring</taglib-uri>
<taglib-location>/WEB-INF/spring.tld</taglib-location>
</taglib>
<!-- Spring Security -->
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
</web-app>
现在,当过我打http://localhost:8080/springhibernate/user/login.do 它为我登录页面,但点击时登录它总是给我的错误
所请求的资源(/springhibernate/user/j_spring_security_check)不可用。 页面重定向到http://localhost:8080/springhibernate/user/j_spring_security_check
请帮我解决这个问题,并建议我如何登录功能,可在我的应用程序被implimented我坚持了下来
我已经直接包含身份验证提供者,因为我在博客上该经理所需的春季版本3的地方阅读*不低于 – viren 2012-01-11 08:57:16
我试着用但同样的问题在那里:( – viren 2012-01-11 09:13:22
@viren - 看到我的配置发布。这些对我来说很好。 – 2012-01-11 09:23:26