字符串内部的Java字符串

Question

编写一个程序，要求用户输入两个字符串，并打印出第二个字符串出现在第一个字符串内的次数。例如，如果第一个字符串是“香蕉”，第二是“一”，该程序将打印2

下面是我到目前为止的代码

public class Assignment4 { 

    /** 
    * @param args the command line arguments 
    */ 
    public static void main(String[] args) { 
     // TODO code application logic here 

     Scanner answer = new Scanner(System.in); 

//Prompt the user to enter a string 
     System.out.println("Enter a word:"); 
     String input = answer.nextLine(); 

//Ask the user to enter a second String 
     //look at index method of string 
     System.out.println("Enter another word:"); 
     String input2nd = answer.nextLine(); 
     int counter = 0; 
     for(int i=0; i<input.length(); i++) { 
      if(input.charAt(i) == input2nd.charAt(0)) { 
       counter++; 

      } 
     } 
     System.out.println(input2nd + " appears " + counter + " times."); 

当我键入香蕉切成第一串，和第二个字符串是“an”，唯一出现的是数字3，它是出现3次的字符a，但不是2，因为它假设只是2“an”

Answer 1

考虑这个技巧，前：

1. 替换由emptychars原词搜索词...
2. 得到两者的长度之间的差异...搜索字符和原来与搜索词的LEN换成
3. 除以...

private static void searchString() { 
Scanner answer = new Scanner(System.in); 
// Prompt the user to enter a string 
System.out.println("Enter a word:"); 
String input = answer.nextLine(); 

// Ask the user to enter a second String 
// look at index method of string 
System.out.println("Enter another word:"); 
String input2nd = answer.nextLine(); 
String a = input.replace(input2nd, ""); 
int counter = (input.length() - a.length())/input2nd.length(); 
System.out.println(input2nd + " appears " + counter + " times."); 
} 

与输入香蕉和一个将打印2