检查2列脚本快速运行

Question

我有一个脚本，用于检查2个文本文件并打印出共同的字段。不过，我觉得它不够快，我正在寻求优化。

FILE1（10k行，3列）和FILE2（200k行，2列），两个文件（csv文件）共有1个字段。

FILE1：

92073263d，86674404000555506123，通信

FILE2：

163738212,7a93632111w7-01e7-40e7-9387-1863e7683eca 63729jd83,07633221122c-6598-4489-B539-​​e42e2dcb3235 8djdy37w8,2b8retyre396-2472-4b2d-8d07-e170fa3d1f64 92073263d，07633221122c-6ew8-4eww-B539-​​e42dsadsadsa

with open('FILE1') as file1: 
    file1_contents = { tuple(line.split(',')) for line in file1 } 
    print file1_contents 

with open('FILE2') as file2: 
    for line in file2: 
     c1,c2 = line.split() 
    if c1 in file1_contents: 
      f = open("FILE3","w") 
      f.write(c2) 
      f.close() 

如果file1_contents中的c1给我一个困难时间，我想避免任何嵌套循环来保持高速度。任何建议？

Answer 1

感谢COLDSPEED again..here是我的新代码：

import pandas 

data_comreport= pandas.read_csv('FILE1', sep = ',', header = 0) 
data_db= pandas.read_csv('FILE2', sep = ',', header = None) 
data_db.columns = ['SerialNumber', 'GUID'] 
data = pandas.merge(data_db,data_comreport,left_on = 'SerialNumber', right_on='SerialNumber', how='inner') 
print data 
#result = data.loc[data['FailureReason'] != ['Failure to export']] 
#if result != None: 
clean_data=data.to_csv('list.txt',index=False, columns=['GUID'],header = None)