2017-10-17 55 views
1

为什么在作为脚本运行putStr (printf "abc%d\n" 3)3含糊不清,但在运行ghci时不是含糊不清?也就是说,为什么我必须在脚本中声明3的类型,而不是ghci?为什么数字类型必须在printf(与putStr一起使用)中为脚本声明,而不是在ghci中声明?

这里是内ghci操作:

$ ghci 
GHCi, version 7.6.3: http://www.haskell.org/ghc/ :? for help 
Loading package ghc-prim ... linking ... done. 
Loading package integer-gmp ... linking ... done. 
Loading package base ... linking ... done. 
Prelude> putStr "abc3\n" 
abc3 
Prelude> import Text.Printf 
Prelude Text.Printf> printf "abc%d\n" 3 
abc3 
Prelude Text.Printf> let main = putStr (printf "abc%d\n" 3) 
Prelude Text.Printf> main 
abc3 
Prelude Text.Printf> let main = printf "abc%d\n" 3 :: String 
Prelude Text.Printf> main 
"abc3\n" 
Prelude Text.Printf> :quit 
Leaving GHCi. 

这里是script的正确的操作,Int声明时:

$ cat runmain-good 
#!/usr/bin/env runghc 
import Text.Printf 
main = putStr (printf "abc%d\n" (3 :: Int)) 
$ ./runmain-good 
abc3 

下面是当3类型是script的错误操作暧昧......与典型的用户友好的Haskell错误:

$ cat runmain-bad 
#!/usr/bin/env runghc 
import Text.Printf 
main = putStr (printf "abc%d\n" 3) 
$ ./runmain-bad 

runmain-bad:3:16: 
    No instance for (PrintfArg a0) arising from a use of `printf' 
    The type variable `a0' is ambiguous 
    Possible fix: add a type signature that fixes these type variable(s) 
    Note: there are several potential instances: 
     instance [safe] PrintfArg Char -- Defined in `Text.Printf' 
     instance [safe] PrintfArg Double -- Defined in `Text.Printf' 
     instance [safe] PrintfArg Float -- Defined in `Text.Printf' 
     ...plus 12 others 
    In the first argument of `putStr', namely `(printf "abc%d" 3)' 
    In the expression: putStr (printf "abc%d" 3) 
    In an equation for `main': main = putStr (printf "abc%d" 3) 

runmain-bad:3:33: 
    No instance for (Num a0) arising from the literal `3' 
    The type variable `a0' is ambiguous 
    Possible fix: add a type signature that fixes these type variable(s) 
    Note: there are several potential instances: 
     instance Num Double -- Defined in `GHC.Float' 
     instance Num Float -- Defined in `GHC.Float' 
     instance Integral a => Num (GHC.Real.Ratio a) 
     -- Defined in `GHC.Real' 
     ...plus 11 others 
    In the second argument of `printf', namely `3' 
    In the first argument of `putStr', namely `(printf "abc%d" 3)' 
    In the expression: putStr (printf "abc%d" 3) 
+0

你知道putStr是不需要的吗? – augustss

+0

谢谢@augustss。我没有意识到这一点。我刚试过你的小费。当然,删除'putStr'不会消除_literal 3含糊错误。但是现在正确的表达式简化为'main = printf“abc%d \ n”(3 :: Int)'。 ... Haskell的数学简洁性是其最美丽的特征之一,因为它有助于阐明算法的本质,尤其是在强烈使用Hindley-Milner的情况下,尽管在这种情况下数字不能被消除。 –

回答

4

GHCi只是简单地放宽了默认启用的默认规则(所以文字5默认为Integer),只是为了让您的生活更轻松。

通过启用ExtendedDefaultRules,您可以在GHC中实现类似的效果。

请参阅GCHi docs以获得更详细的讨论。

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