如何使用PowerShell为多个子目录创建目录连接？

Question

有很多子文件夹，并且只能为二阶子文件夹创建目录连接。

当前文件夹结构的某些部分如下所示

C:\MainFolder>tree 
Folder PATH listing for volume C System 
C:. 
├───1stSub-FolderA 
│ ├───2ndSub-FolderA 
│ └───2ndSub-FolderB 
└───1stSub-FolderB 
    ├───2ndSub-FolderA 
    └───2ndSub-FolderB 

D:\MainFolder-Copy>tree 
Folder PATH listing for volume Dosya 
D:. 
├───1stSub-FolderA 
└───1stSub-FolderB 

手册编码为每个文件夹：

C:\>mklink /j D:\MainFolder-Copy\1stSub-FolderA\2ndSub-FolderA C:\MainFolder\1stSub-FolderA\2ndSub-FolderA 
Junction created for D:\MainFolder-Copy\1stSub-FolderA\2ndSub-FolderA <<===>> C:\MainFolder\1stSub-FolderA\2ndSub-FolderA 

C:\>mklink /j D:\MainFolder-Copy\1stSub-FolderA\2ndSub-FolderB C:\MainFolder\1stSub-FolderA\2ndSub-FolderB 
Junction created for D:\MainFolder-Copy\1stSub-FolderA\2ndSub-FolderB <<===>> C:\MainFolder\1stSub-FolderA\2ndSub-FolderB 

C:\>mklink /j D:\MainFolder-Copy\1stSub-FolderB\2ndSub-FolderA C:\MainFolder\1stSub-FolderB\2ndSub-FolderA 
Junction created for D:\MainFolder-Copy\1stSub-FolderB\2ndSub-FolderA <<===>> C:\MainFolder\1stSub-FolderB\2ndSub-FolderA 

C:\>mklink /j D:\MainFolder-Copy\1stSub-FolderB\2ndSub-FolderB C:\MainFolder\1stSub-FolderB\2ndSub-FolderB 
Junction created for D:\MainFolder-Copy\1stSub-FolderB\2ndSub-FolderB <<===>> C:\MainFolder\1stSub-FolderB\2ndSub-FolderB 

结果：

C:\MainFolder>tree 
Folder PATH listing for volume C System 
C:. 
├───1stSub-FolderA 
│ ├───2ndSub-FolderA 
│ └───2ndSub-FolderB 
└───1stSub-FolderB 
    ├───2ndSub-FolderA 
    └───2ndSub-FolderB 

D:\MainFolder-Copy>tree 
Folder PATH listing for volume Dosya 
D:. 
├───1stSub-FolderA 
│ ├───2ndSub-FolderA 
│ └───2ndSub-FolderB 
└───1stSub-FolderB 
    ├───2ndSub-FolderA 
    └───2ndSub-FolderB 

如何使它对一切都只是第二订购子文件夹几个命令，而不是手动为每个文件夹写代码？命令不应该为第1，第3，第4，第5 ...个子文件夹创建目录结点。

Answer 1

试试这个：

Get-ChildItem D:\MainFolder-Copy -Directory | 
    Foreach {Get-ChildItem (Join-Path C:\MainFolder $_.Name) -Directory} | 
    Foreach {cmd /c mklink /j ($_.FullName -replace 'C:\\MainFolder','D:\MainFolder-Copy') $_.FullName}