我想了解游戏是完成还是绘制或仍然可玩。但我想用动态代码来做到这一点。我如何在tictactoe游戏中做check_game_state方法?
例如我做静态3 * 3井字游戏这样的:
private static boolean check_game_state(char[] board)
{
if ( (board[0]==cSymbol && board[1]==cSymbol && board[2]==cSymbol)
|| (board[3]==cSymbol && board[4]==cSymbol && board[5]==cSymbol)
|| (board[6]==cSymbol && board[7]==cSymbol && board[8]==cSymbol)
|| (board[0]==cSymbol && board[3]==cSymbol && board[6]==(cSymbol))
|| (board[1]==(cSymbol) && board[4]==(cSymbol) && board[7]==(cSymbol))
|| (board[2]==(cSymbol) && board[5]==(cSymbol) && board[8]==(cSymbol))
|| (board[0]==(cSymbol) && board[4]==(cSymbol) && board[8]==(cSymbol))
|| (board[2]==(cSymbol) && board[4]==(cSymbol) && board[6]==(cSymbol)))
{
if (cSymbol == 'X')
{
state = 5; //player 1 win
}
else if (cSymbol == 'O')
{
state = 4; player 2 win
}
}
}
我想将其动态地为4×4或5×5或更高板。但我该怎么做呢?可能吗?
这个家庭作业? – Jivings
在android中期项目的一小块:)我做它静态3 * 3与minimax alg –