如何根据最重复的值对数组进行排序?基于频率对数组进行排序
suppose I have an array [3, 3, 3, 3, 4, 4]
Expected the result as [3, 4] since 3 is most repeated and 4 is least repeated.
有什么办法也做呢?
在此先感谢....!
如何根据最重复的值对数组进行排序?基于频率对数组进行排序
suppose I have an array [3, 3, 3, 3, 4, 4]
Expected the result as [3, 4] since 3 is most repeated and 4 is least repeated.
有什么办法也做呢?
在此先感谢....!
这里是做的一种方法:
distictList
:获得从所述阵列和存储所有不同值在该
countArray
:对于每个i
个索引中distinctList
countArray[i]
保持distinctList[i]
现在排序countArray
并同时在distinctList
上应用相同的交换。
实施例:[3,3,4,4,4]
distinctList [3,4]
countArray [2,3]
降序排序countArray [3,2]排序distinctList同时[4,3] 输出:[4,3]`
简单在Python:
data = [3, 2, 3, 4, 2, 1, 3]
frequencies = {x:0 for x in data}
for x in data:
frequencies[x] = frequencies[x] + 1
sorted_with_repetitions = sorted(data, key=lambda x:frequencies[x],reverse=True)
sorted_without_repetitions = sorted(frequencies.keys(), key=lambda x:frequencies[x],reverse=True)
print(data)
print(sorted_with_repetitions)
print(sorted_without_repetitions)
print(frequencies)
同样的方法(用于收集不同值并计数出现次数的关联容器,用于自定义比较以使用原始数据或只有不同项目对数组进行排序)适用于Java。
它们是否按排序? – Vishy
@Vishy:尚未排序,它可能也是[3,2,3,4,2,1,3] –
什么语言?在Python中,你只需要'[k for k,v in collections.Counter(arr).most_common()]' – nneonneo