使用至少一个电子邮件地址获取所有联系人（DISTINCT）

Question

我正在为自定义首选项编写ContactPickerDialog。

根据首选项，ContactPickerDialog应显示至少一个电话号码的所有联系人或至少一个电子邮件地址的所有联系人。不管有多少电话号码或电子邮件地址与此联系人连接，都不应显示两次联系人。

我有至少一个电话号码与所有联系人的问题没有问题，因为我可以在where-clause中使用HAS_PHONE_NUMBER。但我不知道如何获得至少有一个电子邮件地址的联系人，如果他们有多个电子邮件地址，而没有多次联系一些联系人。

这是我的代码：

public void LoadContactsWithTarget(Context context, PickContactDialog.PickTarget pickTarget) 
{ 
    try 
    { 
     String[] projection = new String[] 
     { 
      ContactsContract.Contacts.DISPLAY_NAME, 
      ContactsContract.Contacts.PHOTO_THUMBNAIL_URI, 
      ContactsContract.Contacts.PHOTO_URI, 
      ContactsContract.Contacts._ID 
     }; 

    String sortOrder = ContactsContract.Contacts.DISPLAY_NAME + " ASC"; 

    Uri uri = null; 
    String where = ""; 
    if (pickTarget == PickTarget.PHONE_NR) 
    { 
     // works great, I only get one contact, no matter how many phone-numbers are connected with this contact 
     uri = ContactsContract.Contacts.CONTENT_URI; 
     where = ContactsContract.Contacts.HAS_PHONE_NUMBER + " = 1"; 
    } 
    else if (pickTarget == PickTarget.EMAIL) 
    { 
     // I get one contact/entry for each eMail-address that is connected with the contact but I only want to get one contact, no matter how many eMail-addresse are connected with the contact 
     uri = ContactsContract.CommonDataKinds.Email.CONTENT_URI; 
     where = ContactsContract.CommonDataKinds.Email.DATA + " NOT LIKE ''";    
    } 

    Cursor cursor = context.getContentResolver().query(uri, projection, where, null, sortOrder); 

    if (cursor.moveToFirst()) 
    { 
     int iNameColumn  = cursor.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME); 
     int iThumbnailColumn = cursor.getColumnIndex(ContactsContract.Contacts.PHOTO_THUMBNAIL_URI); 
     int iImageColumn  = cursor.getColumnIndex(ContactsContract.Contacts.PHOTO_URI);    
     int iIDColumn  = cursor.getColumnIndex(ContactsContract.Contacts._ID); 

     while (!cursor.isAfterLast()) 
     { 
      Contact contact = new Contact(cursor.getInt(iIDColumn), 
              cursor.getString(iNameColumn), 
              cursor.getString(iThumbnailColumn), 
              cursor.getString(iImageColumn)); 

      _lstContacts.add(contact); 

      cursor.moveToNext(); 
     } 
    } 

    cursor.close(); 
} 
catch(Exception e) { } 
} 

任何帮助，非常感谢

Answer 1

  cursorContacts = contentResolver.query(ContactsContract.Data.CONTENT_URI, 
        new String[]{ContactsContract.Data.CONTACT_ID, 
           ContactsContract.Contacts.DISPLAY_NAME, 
           ContactsContract.Data.MIMETYPE, 
           ContactsContract.Contacts.Data.DATA1}, 
        "("+ContactsContract.RawContacts.Data.MIMETYPE + "=?" 
         +" OR "+ContactsContract.RawContacts.Data.MIMETYPE + "=?)" 
        +" AND "+ContactsContract.Data.CONTACT_ID 
          +" IN (SELECT "+ContactsContract.Data.CONTACT_ID 
            +" FROM view_data" 
            +" WHERE "+ContactsContract.Data.MIMETYPE+"=?" 
               +" AND "+ContactsContract.Contacts.Data.DATA1+" NOT NULL" 
               +" AND "+ContactsContract.Contacts.Data.DATA1+" NOT LIKE ''" 
          +")" 
        , 
        new String[]{ContactsContract.CommonDataKinds.Phone.CONTENT_ITEM_TYPE, 
           ContactsContract.CommonDataKinds.Email.CONTENT_ITEM_TYPE, 
           ContactsContract.CommonDataKinds.Email.CONTENT_ITEM_TYPE, 
           }, 
        ContactsContract.Contacts.DISPLAY_NAME);