交叉编译使用NDK，未定义的引用le32toh和be32toh

我试图构建一个共享库，最终的交叉编译一段代码，用来引用be32toh和le32toh。如果我建立这一段代码，并创建一个可执行文件出来吧，我没有得到任何错误：交叉编译使用NDK，未定义的引用le32toh和be32toh

include $(CLEAR_VARS) 
    LOCAL_SRC_FILES:= ubertooth.c ubertooth_helper.c 
    LOCAL_MODULE := ubertooth 
    LOCAL_C_INCLUDES += jni/libusb jni/libbtbb 
    LOCAL_SHARED_LIBRARIES := libc libusb libbtbb 
    LOCAL_LDLIBS := -L$(SYSROOT)/usr/lib -llog 
    include $(BUILD_EXECUTABLE)

这编译成功：

Compile thumb : ubertooth <= ubertooth.c 
    Compile thumb : ubertooth <= ubertooth_helper.c 
    Executable  : ubertooth 
    Install  : ubertooth => libs/armeabi/ubertooth

然而，当我试图把它做成一个共享库仅通过改变在Android.mk一行：

include $(CLEAR_VARS) 
    ... 
    include $(BUILD_SHARED_LIBRARY)

我现在得到以下错误：

Compile thumb : ubertooth <= ubertooth.c 
    Compile thumb : ubertooth <= ubertooth_helper.c 
    SharedLibrary : libubertooth.so 
    ./obj/local/armeabi/objs-debug/ubertooth/ubertooth.o: In function `stream_rx_file': 
    ubertooth.c:224: undefined reference to `be32toh' 
    ./obj/local/armeabi/objs-debug/ubertooth/ubertooth.o: In function `cb_lap': 
    ubertooth.c:281: undefined reference to `le32toh' 
    ./obj/local/armeabi/objs-debug/ubertooth/ubertooth.o: In function `cb_hop': 
    ubertooth.c:417: undefined reference to `le32toh' 
    ./obj/local/armeabi/objs-debug/ubertooth/ubertooth.o: In function `cb_btle': 
    ubertooth.c:506: undefined reference to `le32toh' 
    collect2: ld returned 1 exit status

我不明白为什么我会在构建共享库时得到此链接错误，而不是在构建可执行文件时。而且，如果我想构建共享库，如何正确链接到我缺少的东西？

Here is ubertooth.c

来源

2012-07-28 gnychis

什么当你使用“ndk-build V = 1”构建一个可执行文件和共享库时，它的区别是什么？有不同的D标志吗？ – wojciii 2012-07-28 17:09:06

很好，显然这些宏被命名为不同的NDK在sys/endian.h发现：

__uint64_t htobe64(__uint64_t); 
__uint32_t htobe32(__uint32_t); 
__uint16_t htobe16(__uint16_t); 
__uint64_t betoh64(__uint64_t); 
__uint32_t betoh32(__uint32_t); 
__uint16_t betoh16(__uint16_t); 

__uint64_t htole64(__uint64_t); 
__uint32_t htole32(__uint32_t); 
__uint16_t htole16(__uint16_t); 
__uint64_t letoh64(__uint64_t); 
__uint32_t letoh32(__uint32_t); 
__uint16_t letoh16(__uint16_t);

所以，我用letoh32和betoh32

来源

2012-07-28 16:37:26 gnychis

交叉编译使用NDK，未定义的引用le32toh和be32toh

回答

相关问题